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Rina8888 [55]
3 years ago
13

Find two geometric means between 4 and 13.5

Mathematics
2 answers:
mr_godi [17]3 years ago
8 0
<span>so r1/4 = 13.5/r2 = r2/r1 

r1*r2 = 54 ----------eqn(1) 

r2^2 = 13.5r1--------eqn(2) 

from(2) r1 = r2^2/13.5 

substituting this in eqn(1) 

r2^3/13.5 = 54 

r2^3 = 54*13.5 = 729 

r2 = 9 

r1 = 81/13.5 = 6 

so two geometric means between 4, 13.5 are 6 and 9</span>
dalvyx [7]3 years ago
6 0
<span> two geometric means between 4, 13.5 are 6 and 9</span>
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Iteru [2.4K]

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360,360

Step-by-step explanation:

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For the first spot, we can choose from any of the 15 bands, so we have 15 choices.

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6 0
4 years ago
X + 2y = 5<br>3x + 5y = 14<br>Solve the system of equations.<br>(3.1)<br>(7.-1)<br>(2.3/2)​
son4ous [18]

Answer:

(3,1) because x is 3 and y is 1.

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5 0
3 years ago
point f has coordinated (8,-1), point g is symmetric to point f with respect to the line y=x, what are the coordinates of point
Alex17521 [72]
If points f and g are symmetric with respect to the line y=x, then the line connecting f and g is perpendicular to y=x, and f and g are equidistant from y=x.

This problem could be solved graphically by graphing y=x and (8,-1).  With a ruler, measure the perpendicular distance from y=x of (8,-1), and then plot point g that distance from y=x in the opposite direction.  Read the coordinates of point g from the graph.

Alternatively, calculate the distance from y=x of (8,-1).  As before, this distance is perpendicular to y=x and is measured along the line y= -x + b, where b is the vertical intercept of this line.  What is b?  y = -x + b must be satisfied by (8,-1):  -1 = -8 + b, or b = 7.  Then the line thru (8,-1) perpendicular to y=x is     y = -x + 7.  Where does this line intersect y = x?

y = x = y = -x + 7, or 2x = 7, or x = 3.5.  Since y=x, the point of intersection of y=x and y= -x + 7 is (3.5, 3.5).

Use the distance formula to determine the distance between (3.5, 3.5) and (8, -1).  This produces the answer to this question.

 
7 0
3 years ago
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