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likoan [24]
3 years ago
14

Helpp!!!!! 98 points !!!

Mathematics
2 answers:
Anestetic [448]3 years ago
6 0

Answer:

they don't know the correct length for ad, and they just guessed

Step-by-step explanation:

Mnenie [13.5K]3 years ago
5 0

Answer:

they don't know the correct length for ad, and they just guessed

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9. The graph of a function p(x) is shown. Draw the graph of -p(x - 1)-3.<br>​
djyliett [7]

I'll tell you which transformation you have to apply to draw the new graph:

p(x) \to p(x-1)

Transformations like f(x)\to f(x+k) translate the function horizontally, k units right if k is negative, k units left if k is positive. In this case, k is negative, so you shift the graph 1 unit to the right.

p(x-1) \to -p(x-1)

Transformations like f(x)\to kf(x) stretch the function vertically. If k is negative, they also reflect the graph about the x axis. In this case, k is -1, so you reflect the graph and then stretch with factor 1 (i.e. you don't stretch). So, you reflect the graph about the x axis.

-p(x-1) \to -p(x-1)-3

Transformations like f(x)\to f(x)+k translate the function vertically, k units down if k is negative, k units up if k is positive. In this case, k is negative, so you shift the graph 3 unit down.

Follow the bold instruction (in that order!) and you'll have the graph of the new function.

8 0
4 years ago
Please help me this is for a grade
IgorC [24]

Answer:

b

Step-by-step explanation:

4 0
3 years ago
riangle STV was dilated with the origin as the center of dilation to form S'T'V'. What is the scale factor of the dilation?
omeli [17]
The rule for dilation (scale factor k) about the origin is given by:
(x,y)->(kx,ky)
The scale factor k is therefore obtained by dividing the corresponding coordinates of the image by those of the preimage, namely
scale factor = k = \frac{OS'}{OS}=\frac{OT'}{OT}=\frac{PV'}{OV}
where O is the origin (0,0)
3 0
4 years ago
Which of the following is the simplified form of fifth root of x times the fifth root of x times the fifth root of x times the f
Juliette [100K]

Answer:

\large\boxed{x^\frac{4}{5}}

Step-by-step explanation:

\sqrt[n]{a}=a^\frac{1}{n}\Rightarrow\sqrt[5]{x}=x^\frac{1}{5}\\\\\sqrt[5]{x}\cdot\sqrt[5]{x}\cdot\sqrt[5]{x}\cdot\sqrt[5]{x}=x^\frac{1}{5}\cdot x^\frac{1}{5}\cdot x^\frac{1}{5}\cdot x^\frac{1}{5}\qquad\text{use}\ a^n\cdot a^m=a^{n+m}\\\\=x^{\frac{1}{5}+\frac{1}{5}+\frac{1}{5}+\frac{1}{5}}=x^\frac{4}{5}

4 0
3 years ago
Read 2 more answers
Write the expression with your terms. 10x-2x
vfiekz [6]

Answer:

Step-by-step explanation: first you do 10 minus 2 you get 8

8 0
3 years ago
Read 2 more answers
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