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SSSSS [86.1K]
3 years ago
9

Simplify the expression: –3(–7 + 3z)

Mathematics
1 answer:
aleksandrvk [35]3 years ago
5 0

Hey there! I'm happy to help!

We want to multiply each term inside the parentheses by the number on the outside.

-3(-7)=21

-3(3z)=-9z

Therefore, our expression is 21-9z.

Now you know how to use the distributive property! Have a wonderful day! :D

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cehgg A costing system that first assigns costs to activities and then to products is a.job-order costing. b.activity-based cost
Ronch [10]

Answer:b.activity-based costing.

Step-by-step explanation: Activity-based costing is a costing system that first talkies or identifies the activities that are involved in the Manufacturing or in a particular process and them assigns cost to such activities. This type of costing gives high premium or focus on the activities as it assigns cost to products based on the activities that led to the production of the products.

THIS TYPE OF COSTING IS ALSO KNOWN AS ABC APPROACH TO COSTING IT FIRST ASSIGN RESOURCES TO ACTIVITIES AND FROM ACTIVITIES TO PRODUCTS BASED ON THE CONSUMPTION ESTIMATES.

8 0
3 years ago
scarlet is trying to find the height of a dam. she stands 90 meters away from the dam and records the angle of elevation to the
Harlamova29_29 [7]
Make a drawing with a right triangle.

The opposite side, y, is the height of the dam less 1.65 m

The base or adjacent side is 90 m

The angle between the two sides is 90 m.

Then tan (26) = y / 90

y = 90 tan(26) = 90 (0.4877) = 43.90 m

The height of the dam is 43.90m + 1.65m = 45.55 m
5 0
2 years ago
What is the value of tan(60°)? One-half StartRoot 3 EndRoot StartFraction StartRoot 3 EndRoot Over 2 EndFraction StartFraction 1
Ratling [72]

Answer:

\sqrt3

Step-by-step explanation:

To find:

The value of tan60^\circ = ?

Solution:

Kindly consider the equilateral \triangle ABC as attached in the answer area.

Let the side of triangle = a units

Let us draw the perpendicular from vertex A to side BC.

It will divide the side BC in two equal parts.

i.e. BD = DC = \frac{a}{2}

Using Pythagorean Theorem in \triangle ABD:

\text{Hypotenuse}^{2} = \text{Base}^{2} + \text{Perpendicular}^{2}

Side AD = \frac{\sqrt3}{2}a

Using Trigonometric ratio:

tan\theta = \dfrac{Perpendicular}{Base}

tanB = \dfrac{AD}{BD}

Putting the values of AD and BD:

tan60^\circ=\dfrac{\frac{\sqrt3}{2}a}{\frac{1}{2}a}\\\Rightarrow tan60^\circ = \bold{\sqrt3}

5 0
2 years ago
Read 2 more answers
Sixty photos taken at a photo shoot are in black and white. If this represents 15 percent of the total number of photos taken, w
Oduvanchick [21]

If this represents 15 percent of the total number of photos taken, which equation can be used to find the total number of photos? A. 60×4/15×4 = 240/60.

5 0
3 years ago
Read 2 more answers
The surface area of a right circular cone of radius r and height h is S = πr√ r 2 + h 2 , and its volume is V = 1 3 πr2h. What i
kirill115 [55]

Answer:

Required largest volume is 0.407114 unit.

Step-by-step explanation:

Given surface area of a right circular cone of radious r and height h is,

S=\pi r\sqrt{r^2+h^2}

and volume,

V=\frac{1}{3}\pi r^2 h

To find the largest volume if the surface area is S=8 (say), then applying Lagranges multipliers,

f(r,h)=\frac{1}{3}\pi r^2 h

subject to,

g(r,h)=\pi r\sqrt{r^2+h^2}=8\hfill (1)

We know for maximum volume r\neq 0. So let \lambda be the Lagranges multipliers be such that,

f_r=\lambda g_r

\implies \frac{2}{3}\pi r h=\lambda (\pi \sqrt{r^2+h^2}+\frac{\pi r^2}{\sqrt{r^2+h^2}})

\implies \frac{2}{3}r h= \lambda (\sqrt{r^2+h^2}+\frac{ r^2}{\sqrt{r^2+h^2}})\hfill (2)

And,

f_h=\lambda g_h

\implies \frac{1}{3}\pi r^2=\lambda \frac{\pi rh}{\sqrt{r^2+h^2}}

\implies \lambda=\frac{r\sqrt{r^2+h^2}}{3h}\hfill (3)

Substitute (3) in (2) we get,

\frac{2}{3}rh=\frac{r\sqrt{R^2+h^2}}{3h}(\sqrt{R^2+h^2+}+\frac{r^2}{\sqrt{r^2+h^2}})

\implies \frac{2}{3}rh=\frac{r}{3h}(2r^2+h^2)

\implies h^2=2r^2

Substitute this value in (1) we get,

\pi r\sqrt{h^2+r^2}=8

\implies \pi r \sqrt{2r^2+r^2}=8

\implies r=\sqrt{\frac{8}{\pi\sqrt{3}}}\equiv 1.21252

Then,

h=\sqrt{2}(1.21252)\equiv 1.71476

Hence largest volume,

V=\frac{1}{3}\times \pi \times\frac{\pi}{8\sqrt{3}}\times 1.71476=0.407114

3 0
2 years ago
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