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Mrrafil [7]
3 years ago
12

Write the standard form of a line that passes through the given points (4,7) and (0,7)

Mathematics
1 answer:
VARVARA [1.3K]3 years ago
4 0

The slope-intercept form:

y=mx+b

m - slope

b - y-intercept → (0, b).

We have the points (4, 7) and (0, 7) → b = 7.

Calculate the slope:

m=\dfrac{7-7}{0-4}=\dfrac{0}{-4}=0

Therefore we have y=0x+7=7

The standard form: Ax+By=C

<h3>Answer: y = 7.</h3><h3><em>It's a horizontal line.</em></h3>
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What equation represents a line that is parallel to y=3X +5
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3 years ago
The spinner shown has six equal-size sections and is spun twice.
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3 years ago
What is wrong with the following proof? Clearly we know that 1 does not equal 2. What rule of algebra did we break that makes th
Gnoma [55]

An attempt to divide by zero gives a contradictory result

A rule of algebra broken is <u>dividing by zero</u> (leading to a contradiction) and stating a finite result

Reason:

The given calculation is presented as follows;

1. a > 0, b > 0 given

2. a = b given

3. a·b = b²

4. a·b - a² = b² - a²

5. a·(b - a) = (b + a)·(b - a)

6. a = b + a

7. 0 = b

8. b = 2·b

9. 1 = 2

From line 4, the result are;

4. a·b - a² = b² - a² = 0

5. a·(b - a) = (b + a)·(b - a) = 0

On line 6, both sides where divided by (b - a) = 0, which should given an infinite result

Therefore, one rule of algebra broken is dividing by zero to get a finite result

In line 7, we have;

7. 0 = b

From 6. a = b + a, and a = b, we have;

8. b = 2·b

Therefore, line 9 should be;

9. 0 = 2·0; 0 = 0, given that we have;

1 × 0 = 0

2 × 0 = 0

∴ 1 × 0 = 2 × 0

However

  • 1 ≠ 2

In line 9., by dividing by b = 0, again, we have;

  • 9. 1 = 2 (a contradiction)

Therefore, one rule of algebra that is broken is <u>dividing by zero</u> and having a finite result

Learn more about the rules of algebra here:

brainly.com/question/11388301

5 0
3 years ago
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