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pychu [463]
3 years ago
11

R / 5 - 6 equal negative 1​

Mathematics
1 answer:
Fofino [41]3 years ago
4 0

Answer:

R = 25

Step-by-step explanation:

Given

\frac{R}{5} - 6 = - 1

Multiply through by 5 to clear the fraction

R - 30 = - 5 ( add 30 to both sides )

R = 25

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URGENT! WILL GIVE BRAINLY FOR CORRECT ANSWER
Minchanka [31]

Answer:

sorry if im wrong i think wrong numbers. plz check

Step-by-step explanation:

The center of dilation of the question is (-4,-3) .

let say that

x0=-4

y0=-3

Label the image A'B'C'

The new coordinate would be

A(-4,-1)

x=4

y=-1

x'=x0+ 2(x - x0)

x'= -4+ 2(-4 +4)

x'=-4

y'=y0+ 2(y - y0)

y'= -3+ 2(-1 +3)

y'=-3 +4= 1

______________________________

B(-4,-3)

x=-4

y=-3

x'=x0+ 2(x - x0)

x'= -4+ 2(-4 +4)

x'=-4

y'=y0+ 2(y - y0)

y'= -3+ 2(-3 +3)

y'=-3

______________________________

C(-1,-3)

x=-1

y=-3

x'=x0+ 2(x - x0)

x'= -4+ 2(-1 +4)

x'=-4 +6= 2

y'=y0+ 2(y - y0)

y'= -3+ 2(-3 +3)

y'=-3

A'(-4,1)

B'(-4,-3)

C'(2,-3)

3 0
2 years ago
A rectangular table is fivetimes as long as it is wide. if the area is 80ftsquared​,find the length and the width of the table.
SOVA2 [1]
A = L * W
A = 80
L = 5W

80 = W(5W)
80 = 5W^2
80/5 = W^2
16 = W^2
sqrt 16 = W
4 = W <=== width is 4 ft

L = 5W
L = 5(4)
L = 20 <=== length is 20 ft
3 0
3 years ago
What is the length of the hypotenuse of the triangle below?​
Vedmedyk [2.9K]

Answer:

Step-by-step explanation:

So here we have a 45-45-90 triangle.

This a special right triangle were the sides across from the 45 degree angles can be considered x, while the hypotenuse is two square roots of x.

Here since we have the sides across from the 45 degree angle we can conclude that x = 9\sqrt{2}

So if we wanted the hypotenuse we would just plug in this value of x like so:

hyp = x\sqrt{2} \\

hyp = (9\sqrt{2})(\sqrt{2})

hyp = 9(2)\\

hyp = 18

Therefore the hypotenuse is 18.

3 0
3 years ago
Which point would not be a solution to the system of linear inequalities shown below?
Bumek [7]

Answer:

C

Step-by-step explanation: looks right

dont  trust it though

4 0
3 years ago
Write the expression as a single logarithm
vredina [299]

3\log_7y + 4(\log_7x - 5\log_7z)\\\log_7y^{3} + 4(\log_7x - 5\log_7z)\\\log_7y^{3} + 4(\log_7x - \log_7z^{5})\\\log_7y^{3} + 4(\log_7(\frac{x}{z^{5}}))\\\log_7y^{3} + \log_7(\frac{x}{z^{5}})^{4}\\\log_7(y^{3} \times (\frac{x}{z^5{5}})^{4})

4 0
3 years ago
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