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zloy xaker [14]
3 years ago
8

7th term in geometric sequence an=2 5(n-1)

Mathematics
1 answer:
Soloha48 [4]3 years ago
3 0
To find the 7th term, all you have to do is plug it in the equation.

First n would equal 7 because we are looking for the 7th term.

Now, let's plug everything we know into the equation.

a7 = 2+5 * (7-1)

= 2 + 5 * 6

= 2 + 30

= 32

In conclusion, the 7th term would equal 32.
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Which is the simplified form of the expression (6^-2•6^5)^-3
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Answer:

1

Step-by-step explanation:

( {6}^{ - 2}  \times  {6}^{5} ) ^{ - 3}  \\  = ( {6}^{3} )^{ - 3}  \\  =  {6}^{0}  \\  = 1

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20 square root of 270 /4 square root of 3
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Answer:

<u>The most simplified form is 15√10</u>

Step-by-step explanation:

1. Let's simplify the expression:

20√270 ÷ 4√3

20√9 * 30/  4√3 (√270 = √9 * 30)

60 √30/ 4√3

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60/4 √10 ( We cancel √3 in the numerator and in the denominator)

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Find the value of the power. (2/3)3  ​
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Step-by-step explanation:

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Find the equation of a line parallel to line y=6 that passes through the point (-2,-1)
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What is the equation of a line that passes through the points (-3, 4) and (2,8)?
ziro4ka [17]

Given that the line passes through the two points (-3,4) and (2,8)

We need to determine the equation of the line.

<u>Slope:</u>

The slope of the line can be determined using the formula,

m=\frac{y_2-y_1}{x_2-x_1}

Substituting the points (-3,4) and (2,8) in the above formula, we get;

m=\frac{8-4}{2+3}

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<u>Equation of the line:</u>

The equation of the line can be determined using the formula,

y-y_1=m(x-x_1)

Substituting the point (-3,4) and m=\frac{4}{5} in the above formula, we have;

y-4=\frac{4}{5}(x+3)

y-4=\frac{4}{5}x+\frac{12}{5}

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Thus, the equation of the line is y=\frac{4}{5}x+\frac{32}{5}

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3 years ago
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