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Mariana [72]
3 years ago
11

Alice has a box that is 5 inches long, 5 inches wide, and 5 inches tall. How many 1 inch by 1 inch by 1 inch blocks can Alice fi

t into the box?
Mathematics
2 answers:
Alja [10]3 years ago
6 0
125 cubes since the little cubes are all 1 volume you can just say the normal volume.
scoundrel [369]3 years ago
4 0
Alright so this is is quite easy, all we need to do is find the volume of the box, and that will give us the number of blocks required to fill the box. 
To find the volume of a box we need to multiply the height by the depth by the length:
5x5x5 (or 5^3)
= 125 cubic inches
So 125 blocks would fit in the box.
Hope this helps!
- Z
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Of the girls on the Alden Middle School soccer team, % also play on a travel team. How many of the girls on the middle school te
Wewaii [24]

Answer:

The question is incomplete, so I looked for similar ones and found:

<em>Of the 25 girls on the Alden Middle School soccer team, 40% also play on a travel team. How many of the girls on the  middle school team also play on a travel team? </em>

we can solve this the following way:

25 girls on the soccer team x 40% that play on a travel team = 10 girls form the soccer team that play on a travel team

we can also multiply (25 girls x 40) / 100 = 10 girls

we can check our work by:

10 girls / 40% = 25 girls in total

8 0
3 years ago
How do you solve for the segment area in a circle?
Aleks04 [339]
The area of the entire sector of DEF = 60 / 360 * PI * radius^2
sector area = 1 / 6 * 3.14159265... * 20^2
sector area = <span> <span> <span> 209.4395102393 </span> </span> </span>

segment area = sector area - triangle DEF Area
triangle DEF Area = (1/2) * 20 * sine 60 * 20
triangle DEF Area = (1/2) * 0.86603 * 400
triangle DEF Area = <span><span><span>(1/2) * 346.412 </span> </span> </span>
triangle DEF Area = <span> <span> <span> 173.206 </span> </span> </span>

segment area = <span> <span> 209.4395102393 </span> -173.206
</span>
segment area = <span> <span> <span> 36.2335102393 </span> </span> </span>
segment area = 36.23 m

Source:
http://www.1728.org/circsect.htm



6 0
3 years ago
!
Darina [25.2K]

The graph of the equations was plotted using geogebra graphing and attached.

Let x represent the hours weightlifting and y represent the hours doing cardio exercises.

Since he spend a maximum of 20 hours, hence:

x + y ≤ 20   (1)

Also, he spends at least 8 of those hours weightlifting, hence:

x ≥ 8          (2)

He wants to spend no more than 15 hours doing cardio exercises, this is:

y ≤ 15     (3)

The graph of the equations was plotted using geogebra graphing and attached.

Find out more at: brainly.com/question/17178834

3 0
3 years ago
an ostrich egg weighs 2.9 pounds.The difference between the weight of this egg and the weight of an emu egg is 1.6 pounds.write
Alex73 [517]

Answer:

2.9-w=1.6

Step-by-step explanation:

Let w be weight of emu egg in pounds.

We have been given that an ostrich egg weighs 2.9 pounds.The difference between the weight of this egg and the weight of an emu egg is 1.6 pounds.

We can represent this information as:

2.9-w=1.6

Therefore, the equation 2.9-w=1.6 will give us the weight of the emu egg, w, in pounds.

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