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hoa [83]
3 years ago
10

Find the distance between M(–2, 3) and N(8, 2).

Mathematics
1 answer:
MrRissso [65]3 years ago
8 0
You would use the distance formula and get square root of 101

The answer is <span>b) (image #1)
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X + 7y = 21<br> x + 4y = 15<br> Solve the simultaneous equations
Mariulka [41]

<u>Answer</u>:

x = 7, y = 2

<u>Explanation</u>:

equations given:

x + 7y = 21

x + 4y = 15

make "x" the subject:

x + 7y = 21

x = 21 - 7y .........equation 1

x + 4y = 15

x = 15 - 4y .......equation 2

Solving both the equations simultaneously:

15 - 4y = 21 - 7y

-4y + 7y = 21 - 15

3y = 6

y = 6 ÷ 3

y = 2

If y is 2

Then x = 21 -7y;

x = 21 - 7(2)

x = 21 - 14

x = 7

8 0
2 years ago
Read 2 more answers
How will the volume of the pyramid change if each side is multiplied by a factor of 1/2?
slamgirl [31]
D,The volume will be 1/8 times the volume.
4 0
3 years ago
Read 2 more answers
Help!!!!!!!!!!!!!!!!
valkas [14]
Under box 36x + 9, Drag the following:

A.) 9(4x + 1)
D.) (9 . 4x) + (9 . 1)

Under box 9(4x - 1), Drag the following:
B.) (3 . 12x) - (3 . 3)
C.) 36x - 9

Under box (4 . 9x) + (4 . 2), Drag the following:
E.) 4(9x + 2)
F.) 36x + 8

Hope this helps!
5 0
3 years ago
A heated piece of metal cools according to the function c(x) = (.5)x − 11, where x is measured in hours. A device is added that
e-lub [12.9K]
16.5 degrees below the starting temp, whatever that is. If its 0, then -16.5 degrees.

The first equation would be (.5)5-11=-8.5, because the metal has been cooling for 5 hours.

The device that 'aids' in the cooling would be -5-3=-8, because it is a separate variable that cools the metal, so the amount the device cools is independent of the natural cooling amount, and the equation is independent of the natural cooling equation.
You then add -8.5 and -8, because the device has lowered 8.5 degrees and 8 degrees. This equals -16.5 degrees, or a decrease of 16.5 degrees.
7 0
3 years ago
The probability that a certain machine will produce a defective item is 0.20. if a random sample of 20 items is taken from the o
GenaCL600 [577]
Use binomial distribution, with p=0.20, n=20, x=3
P(X=x)=C(n,x)p^x (1-p)^(n-x)

P(X>=3)
=1-(P(X=0)+P(X=1)+P(X=2))
=1-(C(20,0)0.2^0 (0.8)^(20-0)+C(20,1)0.2^1 (0.8)^(20-1)+C(20,2)0.2^2 (0.8)^(20-2))
=1-(0.0115292+0.057646+0.136909)
=1-0.206085
=0.793915
7 0
4 years ago
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