Answer:
The lengths of Gajge’s runs have greater variability because there is a greater difference between his longest and shortest runs is the answer.
Step-by-step explanation:
given that Ty and Gajge are football players.
Carries is 15 for both and average is the same 4 for both.
But on scrutiny we find that maximum and minimum and 6 and 2 for Ty.
Hence range for Ty = 6-2 =4 (2 runs on eithre side of mean)
But for Gajge, highest is 19 and lowest is 2.
i.e. range = 19-2 =17 very much higher than that of Ty
The lengths of Gajge’s runs have greater variability because there is a greater difference between his longest and shortest runs.
Answer:
8
Step-by-step explanation:
(10-4)+20/20
6+20/10
6+2
8
Answer:
3.51 (round to the nearest hundreds)
Step-by-step explanation:
PART A
slope of the line passing through AC : (6-1)/(1-2) = 5/-1 = -5
equation of the line passing through B and perpendicular to AC:
y-3 = 1/5(x-3)
y-3 = 1/5x -3/5
y = 1/5 x - 3/5 + 3
y = 1/5 x + (-3+15)/5
y = 1/5 x + 12/5
PART B
line that passes through the points A and C
y-1 = -5(x-2)
y = -5x+10 + 1
y = -5x + 11
Interception of the lines
y = 1/5x + 12/5
y = -5x + 11
-5x + 11 = 1/5x + 12/5
-25x +55 = x + 12
26x = 43
x = 43/26
y = -5(43/26) + 11
y= -215/26 + 11
y = (-215+286)/26 = 71/26
D (1.65, 2.73)
PART C
AC = 
= 5,09902
BD = 
= 1,376735
PART D
AREA = (5,09902 * 1.376735)/2 = 3,509999
Answer:
See Below
Step-by-step explanation:
1)√8 √10 √15
2)√3/16 √3/4
3)
0.25 R
0.25 R
0.33 R
4)
23 R
pi IR
√400 R
(√36)/2 R if its √(36/2) then IR
5)
pi
√8
Hope this helped!
Answer:
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