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zalisa [80]
3 years ago
14

How will understanding IT help me achieve my goals in life?

Computers and Technology
1 answer:
Oksana_A [137]3 years ago
5 0

I have reported this question. Only because brainly advises me to. Please do not let this offend you. I am just doing what the brainly brochure says.

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Read the following scenario what type of business letter do you think is required in this situation?
grandymaker [24]

Answer:

Cover letter

Explanation:

The type of business letter Melissa and Melrose would need to write is a Cover letter.

The Cover Letter is usually not more than a page document which gives a kind of summary or hint about who individual is and the quality of the individual, while highlighting why an individual is the best fit for the role they are seeking for.

Most recruiters usually make use of the cover letter, as a first hurdle, to screen out applicants especially when applications are much.

Melissa and Melrose, in addition to the resume they would submit for the volunteering job, would need a cover letter.

8 0
3 years ago
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_____ means collecting vast amounts of data from a host of websites.
xenn [34]

Answer:

D

Explanation:

D. Web Scraping is the answer

8 0
2 years ago
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Which formulas would work to combine cells with first, middle, and last names from columns A through C and row 2 into a new cell
AURORKA [14]

Split? not really sure but i understand a bit of this..

6 0
3 years ago
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Problem 2 Write a method that (a) returns an int[] , (b) takes in two sorted arrays (in descending order) and (c) returns an int
Galina-37 [17]

Answer:

Following are the Program in the Java Programming Language.

//define class

public class Main

{

//define function to merge and sort array

public static int[] sort_Array(int[] a, int[] b)

{

//set integer variable and initialize values

int x = 0, y = 0, k = 0, num = 0;

int n = a.length;

int n1 = b.length;

//set integer type array

int[] ar = new int[n+n1];

//set while loop

while (x<n && y <n1)

{

num++;

num++;

//set if conditional statement

if (a[x] > b[y])

ar[k++] = a[x++];

else

ar[k++] = b[y++];

num++;

}

//set the while loop

while (x < n)

{

num++;

ar[k++] = a[x++];

}

//set the while loop

while (y < n1)

{

num++;

ar[k++] = b[y++];

}

//print the total compares done

System.out.println("Number of compares done: " + n);

//return array

return ar;

}

//define main method

public static void main(String[] args)

{

//declaration and the initialization of array

int[] a = new int[]{18,16, 15, 6, 2};

int[] b = new int[]{13, 12, 11, 7, 1};

int[] ar;

//call function

ar = sort_Array(a, b);

//print message

System.out.println("\nThe resultant array is: \n");

//set for loop to print array

for(int x=0; x<ar.length; x++)

{

System.out.print(ar[x] + " ");

}

}

}

<u>Output</u>:

Number of compares done: 5

The resultant array is:

18 16 15 13 12 11 7 6 2 1

Explanation:

Here, we define a class "Main" inside the class, define a function "sort_Array()"and pass two integer type array argument "a" and "b".

  • Set four integer type variables "x", "y", "k", and "num" and initialize them to 0.
  • Set two integer type array "n", "n1" and initialize them the length of the array then, set integer type array variable "ar".
  • Set the while loop then, set if conditional statement then, agin set while loop to sort array in descending order.
  • Then, print the number of compares and return the value of the variable "ar".

Finally, define the main method inside it, we set two integer type array variable and initialize elements in them then, set the for loop to print the sorted elements of the array.

4 0
3 years ago
From the binary search algorithm, it follows that every iteration of the while loop cuts the size of the search list by half.
Colt1911 [192]

Answer:

True: In binary search algorithm, we follow the below steps sequentially:

Input: A sorted array  B[1,2,...n] of n items and one item x to be searched.

Output: The index of x in B if exists in B, 0 otherwise.

  1. low=1
  2. high=n
  3. while( low < high )
  4.  {      mid=low + (high-low)/2
  5.         if( B[mid]==x)
  6.          {
  7.             return(mid)  //returns mid as the index of x
  8.           }
  9.          else
  10.          {
  11.              if( B[mid] < x)      //takes only right half of the array
  12.               {
  13.                 low=mid+1
  14.               }
  15.              else               // takes only the left half of the array
  16.               {
  17.                high=mid-1
  18.               }
  19.           }
  20.  }
  21. return( 0 )

Explanation:

For each iteration the line number 11 or line number 15 will be executed.

Both lines, cut the array size to half of it and takes as the input for next iteration.

6 0
3 years ago
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