Solve sin2x + 2sinx = 0 for 0 ≤ x < 2π. ...?

1 answer:

3 0

Sin 2 x + 2 sin x = 0
2 sin x cos x + 2 sin x = 0 / : 2
sin x cos x + sin x = 0
sin x ( cos x + 1 ) = 0
sin x = 0, cos x + 1 = 0, cos x = - 1;
Answer:
x = 0, or x = π

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