1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Lady bird [3.3K]
4 years ago
9

In the solar panel system presented in the video, which of the following was necessary to generate usable electrical current for

a home?
A- Electrical energy had to be stored in batteries for several days.
B- DC power had to be converted to AC.
C- The electrical energy had to be converted to nuclear energy.
D- The heat of the sun had to be used to generate steam.
Physics
1 answer:
anastassius [24]4 years ago
7 0

Answer:

A and B are both requirements for a solar panel to generate usable current at home.

Explanation:

Solar panel operates through a group of cells, where each one of them captures/convert electrons making them move from one polarised region to another. The excited electrons can move from a region in excess of electrons (p region) to a region with a lack of electrons (n region).  

This physical effect of electron moving from one side to another creates what we know as current flow.

This current flow from a solar panel does not vary with time in a determined frequency, so it's constant. This is the definition of a DC current. Since the household devices work with AC (variable sinusoidal current Alternate Current) a converter DC to AC is required.

Due to the fact that the solar panels only operate in the day when they recibe direct sunlight, there is the need to have batteries to store the energy for the night and the times where the sunlight is not enough to provide enough electron flow.

You might be interested in
The force between two charges, q, and 92, is F. If the distance between the
Sholpan [36]

Answer:

4F

Explanation:

F = kQ₁Q₂/d²

F' = k2Q₁2Q₂/d²

F' = 4(kQ₁Q₂/d²)

F' = 4F

4 0
3 years ago
An air compressor compresses 6 L of air at 120 kPa and 22°C to 1000 kPa and 400°C. Determine the flow work, in kJ/kg, required b
Mariana [72]

Answer:

The work flow required by the compressor = 100.67Kj/kg

Explanation:

The solution to this question is obtained from the energy balance where the initial and final specific internal energies and enthalpies are taken from A-17 table from the given temperatures using interpolation .

The work flow can be determined using the equation:

M1h1 + W = Mh2

U1 + P1alph1 + ◇U + Workflow = U2 + P2alpha2

Workflow = P2alpha2 - P1alpha1

Workflow = (h2 -U2) - (h1 - U1)

Workflow = ( 684.344 - 491.153) - ( 322.483 - 229.964)

Workflow = ( 193.191 - 92.519)Kj/kg

Workflow = 100.672Kj/kg

6 0
4 years ago
Help please hurry! ‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️
eimsori [14]
IV - Temperature
DV - Light intensity
8 0
3 years ago
A brick lands 10.1 m from the base of a building. If it was given an initial velocity of 8.6 m/s [61º above the horizontal], how
Montano1993 [528]
<h2>Answer: 10.52m</h2><h2 />

First, we have to establish the <u>reference system</u>. Let's assume that the building is on the negative y-axis and that the brick was thrown at the origin (see figure attached).

According to this, the initial velocity V_{o} has two components, because the brick was thrown at an angle \alpha=61\º:

V_{ox}=V_{o}cos\alpha   (1)

V_{ox}=8.6\frac{m}{s}cos(61\º)=4.169\frac{m}{s}  (2)

V_{oy}=V_{o}sin\alpha   (3)

V_{oy}=8.6\frac{m}{s}sin(61\º)=7.521\frac{m}{s}   (4)

As this is a projectile motion, we have two principal equations related:

<h2>In the x-axis: </h2>

X=V_{ox}.t  (5)

Where:

X=10.1m is the distance where the brick landed

t is the time in seconds

If we already know X and V_{ox}, we have to find the time (we will need it for the following equation):

t= \frac{X}{ V_{ox}}  (6)

t=2.42s  (7)

<h2>In the y-axis: </h2>

-y=V_{oy}.t+\frac{1}{2}g.t^{2}   (8)

Where:

y is the height of the building (<u>in this case it has a negative sign because of the reference system we chose)</u>

g=-9.8\frac{m}{s^{2}} is the acceleration due gravity

Substituting the known values, including the time we found on equation (7) in equation (8), we will find the height of the building:

-y=(7.521\frac{m}{s})(2.42s)+\frac{1}{2}(-9.8\frac{m}{s^{2}}).(2.42s)^{2}   (9)

-y=-10.52m   (10)

Multiplying by -1 each side of the equation:

y=10.52m >>>>This is the height of the building

3 0
3 years ago
If a jet travels 350 m/s, how far will it travel each second?
77julia77 [94]

Answer:

It will travel 350 meters each second.

Explanation:

The unit rate, 350 m/s, tells us that the jet will travel 350 meters per every second elapsed.

6 0
3 years ago
Read 2 more answers
Other questions:
  • What is Virtual Lab and what does people use it for and why they use it?
    6·1 answer
  • A tray is moved horizontally back and forth in simple harmonic motion at a frequency of f = 2.20 Hz. On this tray is an empty cu
    5·1 answer
  • The Doppler effect is an effect produced by a moving source of sound or electromagnetic waves due to the relative motion of a so
    13·2 answers
  • What is the relationship between height and gravitational potential energy of water behind a dam?
    13·1 answer
  • Calculate the momentum pelephant of a 2140 kg elephant charging a hunter at a speed of 7.63 m/s . pelephant= kg⋅m/s Compare the
    13·1 answer
  • Which of the following is the FINAL step in a forecasting​ system?
    15·1 answer
  • Message body weight 30 points
    13·1 answer
  • A disk-shaped merry-go-round of radius 2.93 m and mass 165 kg rotates freely with an angular speed of 0.691 rev/s . A 62.4 kg pe
    5·2 answers
  • A jeweler needs to electroplate gold onto a bracelet using an ionic solution. He knows that the charge carriers in the ionic sol
    9·1 answer
  • I need help with question ii) Calculate the speed of these radio waves.
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!