1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Paladinen [302]
3 years ago
12

6. A spring whose spring constant is 850 N/m is compressed 0.40 m. What is the maximum

Physics
1 answer:
vladimir2022 [97]3 years ago
7 0

Given :

A spring whose spring constant is 850 N/m is compressed 0.40 m.

To Find :

The maximum speed it can give to 0.50 kg ball.

Solution :

We know, Kinetic energy = Energy stored in spring

\dfrac{mv^2}{2}= \dfrac{kx^2}{2}\\\\v= x\sqrt{\dfrac{k}{m}}\\\\v = 0.40\times \sqrt{\dfrac{850}{0.50}}\\\\v = 16.49\ m/s

Hence, this is the required solution.

You might be interested in
We can predict the path of a hurricane because of the work of which of the following scientists?
musickatia [10]

Answer:C

Explanation:

4 0
3 years ago
How is a magnetable to pick up bits of metal without actually touching them?
lisov135 [29]

C.There is an invisible magnetic field around the magnet where it exerts magnetic force

7 0
3 years ago
Mutations that neither benefit nor harm the organisms have blanks effect on the organisms survival
Rainbow [258]

Answer:

I would say that the mutation has no effect on the organism, as it doesn't help or harm it.

hope this helps :)

8 0
3 years ago
Read 2 more answers
A rectangular loop of wire with width w = 5 cm, length L = 10cm, mass m = 40 g, and resistance R = 20 mΩ has an initial velocity
zhuklara [117]

Answer:

The loop penetrate 4 cm into the magnetic field.

Explanation:

Given that,

Width w= 5 cm

Length L= 10 cm

mass m = 40 g

Resistance R = 20 mΩ

Initial velocity = 1 m/s

Magnetic field = 2 T

We need to calculate the induced emf

Using formula of emf

\epsilon=v_{0}Bw

Put the value into the formula

\epsilon =1\times2\times5\times10^{-2}

\epsilon =10\times10^{-2}\ volt

We need to calculate the current

Using Lenz's formula

i=\dfrac{\epsilon}{R}

i=\dfrac{10\times10^{-2}}{20\times10^{-3}}

i=5\ A

We need to calculate the force

Using formula of force

F=i(\vec{w}\times\vec{B})

F=iwB

Put the value into the formula

F=5\times5\times10^{-2}\times2

F=0.5\ N

We need to calculate the acceleration

Using formula of acceleration

a=\dfrac{F}{m}

Put the value in to the formula

a=\dfrac{0.5}{40\times10^{-3}}

a=12.5\ m/s^2

We need to calculate the distance

Using equation of motion

v^2=u^2+2as

s=\dfrac{v^2-u^2}{2a}

s=\dfrac{0-1^2}{2\times(-12.5)}

s=0.04\ m

s=4\ cm

Hence, The loop penetrate 4 cm into the magnetic field.

5 0
3 years ago
Which of the following scenarios represents the best use of a scientific model?
valkas [14]

Answer:

Predicting weather patterns is the answer :-)

Explanation:

4 0
3 years ago
Other questions:
  • What’s the maximum height of the second hill? Use your answer from part E and the formula PE=m•g•h to determine the answer. Assu
    8·2 answers
  • What are gamma rays used for
    15·2 answers
  • Is an imaginary "line" from the earth to the moon a line, a ray, or a segment? Why?
    6·1 answer
  • A bird can fly 25 km/h. How long does it take to fly 3.5km?
    12·1 answer
  • Please help ASAP. There are 3 question it would be a big help if you can answer any.
    11·2 answers
  • Terrane accretion generally occurs along a ________ boundary between a continental plate and an oceanic plate.
    9·1 answer
  • Giant cave systems have formed through the reaction of acids with the that make up limestone.
    11·2 answers
  • Which term describes an image that is in the opposite orientation than the object from which it was formed? virtual erect invert
    11·1 answer
  • Calculate the escape velocity
    6·1 answer
  • An object is dropped from 600 m. If it is initially at rest and achieves a top speed of 45 m/s just as it hits the ground, what
    8·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!