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horrorfan [7]
3 years ago
15

6.A truck drives to a rock quarry at a speed of 20 m/s. The truck takes on a load of

Physics
1 answer:
Karolina [17]3 years ago
4 0

Explanation:

The kinetic energy is basically the energy possesses by virtue of a body's motion

1. The truck moving to the quarry

let the mass be x

and the velocity is given as 20m/s

we know that the kinetic energy is given as

KE=1/2mv^2

KE=1/2(x)*20^2

KE=1/2(x)400

KE=200x

2. The truck leaving to the quarry

let the mass be 2x

and the velocity is given as 20m/s

we know that the kinetic energy is given as

KE=1/2mv^2

KE=1/2(2x)*20^2

KE=1/2(2x)400

KE=400x

From the analysis the kinetic energy is a function of mass, doubling the mass doubles the kinetic energy

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Answer:

The object starts away from the origin and then moves toward the origin at a constant velocity. Next, it stops for one second. Finally, it moves away from the origin at a greater constant velocity.

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3 years ago
A cat dozes on a stationary merry-go-round, at a radius of 5.5 m from the center of the ride. Then the operator turns on the rid
bixtya [17]

Answer:

u_{s}=0.56

Explanation:

For the cat to stay in place on the merry go round without sliding the magnitude of maximum static friction must be equal to magnitude of centripetal force

F_{s.max}=\frac{mv^2}{r} \\

Where the r is the radius of merry-go-round and v is the tangential speed

but

F_{s.max}=u_{s}F_{N}=u_{s}mg

So we have

u_{s}mg=\frac{mv^2}{r}\\ u_{s}=\frac{v^2}{gr}\\ Where\\v=\frac{2\pi R}{T} \\So\\u_{s}=\frac{(\frac{2\pi R}{T} )^2}{gr} \\u_{s}=\frac{4\pi^2 r}{gT^2}

Substitute the given values

So

u_{s}=\frac{4\pi^2 5.5m}{(9.8m/s^2)(6.3s)^2} \\u_{s}=0.56

6 0
3 years ago
If you touch a hot light bulb and get burned, that is an example of _____.
Anton [14]

The answer is C conduction

7 0
2 years ago
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How do particles move when a surface wave passes through a medium?
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They move in a perpendicular direction to the direction of wave motion. Happy to help!
8 0
1 year ago
A package was determined to have a mass of 5.7 kilograms. What's the force of gravity acting on the package on earth?
Arturiano [62]
1.) The force of gravity is what we call weight, we define it as:
w=mg
w=5,7kg*9,8m/s²
w=55,86kg (b)
2.) We know that:
power=W/t
power=50J/20s
power=2,5Watts (a)
3.) The work done is equal to the potential energy, so:
Epg=mgh
Epg=63kg*9,8m/s²*7m
Epg=4321J
Now we get the power:
power=W/t
power=4321J/5s
power=864Watts
Now:
1HP=746Watts
=1,16HP (b)
4.) We know that:
F=ma
350N=m*10m/s²
m=350N/10m/s²
m=35kg (b)
5.) d.) Aceleration is tha rate of change in velocity, either positive (increasing) or negative (decreasing)
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3 years ago
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