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Zinaida [17]
3 years ago
5

USE THE PICTURE THANKS WILL GIVE B WRONG ANSWER=report lol love ya

Physics
1 answer:
KIM [24]3 years ago
8 0

Answer:

I would have to say B THe su would rise in the west and set in the east But this is just a guess

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Answer:

D is correct

Explanation:

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3 years ago
A 5 kg object near Earth's surface is released from rest such that it falls a distance of 10 m. After the object falls 10 m, it
makkiz [27]

Answer:D

Explanation:

Given

mass of object m=5 kg

Distance traveled h=10 m

velocity acquired v=12 m/s

conserving Energy at the moment when object start falling and when it gains 12 m/s velocity

Initial Energy=mgh=5\times 9.8\times 10=490 J

Final Energy=\frac{1}{2}mv^2+W_{f}

=\frac{1}{2}\cdot 5\cdot 12^2+W_{f}

where W_{f} is friction work if any

490=360+W_{f}

W_{f}=130 J

Since Friction is Present therefore it is a case of Open system and net external Force is zero

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krek1111 [17]

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A 0.150-kg ball traveling horizontally on a frictionless surface approaches a very massive stone at 20.0 m/s perpendicular to wa
Hitman42 [59]

Answer:

The magnitude of the change in momentum of the stone is 5.51kg*m/s.

Explanation:

the final kinetic energy = 1/2(0.15)v^2

                1/2(0.15)v^2  = 70%*1/2(0.15)(20)^2

                              v^2 = 21/0.075

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if u is the initial speed and v is the final speed, then:

u = 20 m/s and v = - 16.73m/s

change in momentum = m(v-u)

                                     = 0.15(- 16.73-20)

                                    = -5.51 kg*m.s

Therefore, The magnitude of the change in momentum of the stone is 5.51kg*m/s.

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