Answer:
0.8J
Explanation:
Given parameters:
Force = 20N
Compression = 0.08m
Unknown:
Spring constant = ?
Elastic potential energy = ?
Solution:
To solve this problem, we use the expression below:
F = k e
F is the force
k is the spring constant
e is the compression
20 = k x 0.08
k = 250N/m
Elastic potential energy;
EPE = 
k e² = x 250 x 0.08²
Elastic potential energy = 0.8J
Answer:
a) P1=100kpa
V1=6m³
V2=?
P2=50kpa
rearranging mathematically the expression for Boyle's law
V2=(P1V1)/P2=(100×6)/50=12m³
b) same apartment as in (a) but only the value of P2 changes
=> V2=(100×6)/40=15m³
Explanation:
since temperature is not changing we use Boyle's law. mathematically expressed as P1V1=P2V2
1 newton-meter is 1 Joule, the unit of work and energy.
Yo sup??
magnitude of original vector is 5 units.
angle made with x axis is 67°
horizontal component=5*cos67°
=5*0.4
=2 units (approx)
Therefore the correct answer is option B
Hope this helps
