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Kaylis [27]
3 years ago
11

Sum.Write a program that prompts the user to read two integers and displays their sum.Your program should prompt the user to rea

d the number again if the input is incorrect.
Computers and Technology
1 answer:
adelina 88 [10]3 years ago
7 0

Answer:

while True:

   number1 = input("Enter the number1: ")

   number2 = input("Enter the number2: ")

   

   if number1.isnumeric() and number2.isnumeric():

       break

 

number1 = int(number1)

number2 = int(number2)

print("The sum is: " + str(number1 + number2))

Explanation:

*The code is in Python.

Create an infinite while loop. Inside the loop, Get the number1 and number2 from the user. Check if they are both numeric values. If they are, stop the loop (Otherwise, the program keeps asking for the numbers).

When the loop is done, convert the numbers to integer numbers

Calculate and print their sum

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1.<br> The correct way to use a seat belt is
Nesterboy [21]

Answer:

4 steps

Explanation:

Step 1: Pull belt across body

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Step 3: Adjust shoulder belt

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Step 4: Check before driving

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4 0
3 years ago
A camera on a tripod shows the ground floor of a skyscraper and then moves upward to show its entire length. what camera movemen
scZoUnD [109]

Answer:

A pedestal. It involves moving the camera upwards or downwards in relation to a subject.

8 0
3 years ago
Create a Java program with threads that looks through a vary large array (100,000,000 elements) to find the smallest number in t
olchik [2.2K]

Answer:

See explaination

Explanation:

import java.util.Random;

public class Sample{

static class MinMax implements Runnable{

int []arr;

int start,end,min,max;

MinMax(int[]arr, int start,int end){

this.start=start;

this.end=end;

min=Integer.MAX_VALUE;

max=Integer.MIN_VALUE;

this.arr=arr;

}

atOverride

public void run() {

for(int i=start;i<=end;i++){ //search min and max form strant to end index

min=Math.min(min,arr[i]);

max=Math.max(max, arr[i]);

}

}

}

public static void main(String[] args) throws Exception{

long beginTime = System.nanoTime();

Random gen = new Random();

int n=100000000;

int[] data = new int[n]; //generate and fill random numbers

for(int i = 0; i < data.length; i++) {

data[i] = gen.nextInt()%1000000;

}

long endTime = System.nanoTime();

System.out.println("Done filling the array. That took " + (endTime - beginTime)/1000000000f + " seconds.");

//-----------------------------------------

System.out.println("Using 1 thread"); //1 thread

MinMax m1=new MinMax(data,0,n-1); //class object

Thread t1=new Thread(m1); //new thread

beginTime=System.nanoTime(); //start timer

t1.start(); //start thread

t1.join(0); //wait until thread finishes

endTime=System.nanoTime(); //end timer

System.out.println("Min,Max: "+m1.min+","+m1.max); //print minimum and maximum

System.out.println("Time using 1 thread " + (endTime - beginTime)/1000000000f + " seconds."); //print time taken

//-----------------------------------------

System.out.println("Using 2 thread");

m1=new MinMax(data,0,n/2);

MinMax m2=new MinMax(data,n/2+1,n-1);

t1=new Thread(m1);

Thread t2=new Thread(m2);

beginTime=System.nanoTime();

t1.start();

t2.start();

t1.join(0);

t2.join(0);

endTime=System.nanoTime();

System.out.println("Min,Max: "+ Math.min(m1.min,m2.min)+","+Math.max(m1.max,m2.max));

System.out.println("Time using 2 thread " + (endTime - beginTime)/1000000000f + " seconds.");

//-----------------------------------------

System.out.println("Using 3 thread");

m1=new MinMax(data,0,n/3);

m2=new MinMax(data,n/3+1,2*n/3);

MinMax m3=new MinMax(data,2*n/3+1,n-1);

t1=new Thread(m1);

t2=new Thread(m2);

Thread t3=new Thread(m3);

beginTime=System.nanoTime();

t1.start();

t2.start();

t3.start();

t1.join(0);

t2.join(0);

t3.join(0);

endTime=System.nanoTime();

System.out.println("Min,Max: "+ Math.min(Math.min(m1.min,m2.min),m3.min)+","+Math.max(Math.max(m1.max,m2.max),m3.max));

System.out.println("Time using 3 thread " + (endTime - beginTime)/1000000000f + " seconds.");

//-----------------------------------------

System.out.println("Using 4 thread");

m1=new MinMax(data,0,n/4);

m2=new MinMax(data,n/4+1,2*n/4);

m3=new MinMax(data,2*n/4+1,3*n/4);

MinMax m4=new MinMax(data,3*n/4+1,n-1);

t1=new Thread(m1);

t2=new Thread(m2);

t3=new Thread(m3);

Thread t4=new Thread(m4);

beginTime=System.nanoTime();

t1.start();

t2.start();

t3.start();

t4.start();

t1.join(0);

t2.join(0);

t3.join(0);

t4.join(0);

endTime=System.nanoTime();

System.out.println("Min,Max: "+ Math.min(Math.min(m1.min,m2.min),Math.min(m3.min,m4.min))+","+Math.max(Math.max(m1.max,m2.max),Math.max(m3.max,m4.max)));

System.out.println("Time using 4 thread " + (endTime - beginTime)/1000000000f + " seconds.");

}

}

6 0
3 years ago
Sharing a workbook enables multiple users to access the workbook. What are the benefits of using a shared workbook?
damaskus [11]

Answer:

Some of the benefits of sharing a workbook include:

A. Shared information between students (ie: Mary writes a note about (blank) in the workbook and John reads said note and receives addition information about (blank)).

B. ^adding onto this, discussion on interpretations of a passage (ie: John thinks (blank) means this and Mary thinks (blank) means other thing, through notes they can discuss the meaning of the text.

Hope this helps. =)

8 0
4 years ago
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