Point sloe is
y-y1=m(x-x1)
slope=m
a ponint is (x1,y1)
slope=(y2-y1)/(x2-x1)
(x,y)
(5,-3)
(-2,9)
slope=(9-(-3))/(-2-5)=12/-7=-12/7
m=-12/7
a point is (5,-3)
x1=5
y=-3
y-(-3)=-12/7(x-5)
y+3=-12/7(x-5)
2nd one
N₁*$0.10 + n₂*$0.25 = $2.25
n₁ + n₂ = 12
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This means that:
n₁ = 12 - n₂
And:
(12 - n₂)*$0.10 + n₂*$0.25 = $2.25
12*$0.10 - n₂*$0.10 + n₂*$0.25 = $2.25
$1.20 + n₂*$0.05*(5-2) = $2.25
$1.20 + n₂*$0.05*3 = $2.25
$1.20 + n₂*$0.15 = $2.25
n₂*$0.15 = $2.25 - $1.20
n₂*$0.15 = $1.05
n₂ = ($1.05)/($0.15)
n₂ = 7
If n₂ = 7:
n₁ + 7 = 12
Therefore, n₁ = 5.
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Answer:
5 dimes and 7 quarters.
Answer:
t = 2
Step-by-step explanation:
have a nice day:)
The equation of a circle is:
(x-h)^2 + (y-k)^2 = r^2
where (h,k) is the location of the center and r is the radius. So we need to find h, k, and r. The center is given as (5,-4) so h = 5 and k = -4:
(x-5)^2 + (y-(-4))^2 = r^2
(x-5)^2 + (y+4)^2 = r^2
So we need to find r. Use the distance formula to find the distance between (5,-4) and (-3,2):
r = [(5-(-3))^2+((-4)-2)^2]^1/2
r = [8^2 + (-6)^2]^1/2
r = [64 + 36]^1/2
r = 100^1/2
r= 10
The final equation is:
(x-5)^2 + (y+4)^2 = 10^2
