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stellarik [79]
3 years ago
14

The area of a square quilt is 289 square inches. There is a smaller square patch on the quilt with an area of 121 square inches.

What is the difference between the overall perimeter of the quilt and the perimeter of the smaller square patch?
Mathematics
2 answers:
nadezda [96]3 years ago
8 0
The answer is 42, 289/4=72.25, then 121/4=30.25
so we subtract the answers, 72.25-20.25= 42
answer=42
alisha [4.7K]3 years ago
3 0
Area of a square quilt = 289 square inches
Area of a smaller square quilt = 121 square inches

Area of a square = a²

Side length of big square quilt = √289 in² = 17 inches
side length of small square quilt = √121 in² = 11 inches

Perimeter of big square = 17 inches * 4 = 68 inches
perimeter of small square = 11 inches * 4 = 44 inches

difference = 68 inches - 44 inches = 24 inches.
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Step-by-step explanation:

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Suppose you are the manager of a firm. The accounting department has provided cost​ estimates, and the sales department sales​ e
Katarina [22]

Answer:

<em>If more than 134 articles are produced and sold, the firm will have positive profits and shoule start production</em>

Step-by-step explanation:

Cost, Revenue, and Profit Function

The cost function C(x) is given by

C(x)=75x+3,350

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R(x)=100x

With both equations, we can know the profit function as

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P(x)=100x-75x-3,350=25x-3,350

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For the firm to have positive profits, it has to produce x articles with the condition

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P(x)=25x-3,350>0

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\displaystyle x>\frac{3,350}{25}

Thus

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6 0
3 years ago
(5) Find the Laplace transform of the following time functions: (a) f(t) = 20.5 + 10t + t 2 + δ(t), where δ(t) is the unit impul
Aloiza [94]

Answer

(a) F(s) = \frac{20.5}{s} - \frac{10}{s^2} - \frac{2}{s^3}

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Step-by-step explanation:

(a) f(t) = 20.5 + 10t + t^2 + δ(t)

where δ(t) = unit impulse function

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F(s) = \int\limits^a_0 f(s)e^{-st} \, dt

where a = ∞

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where d(t) = δ(t)

=> F(s) = \int\limits^a_0 {(20.5e^{-st} + 10te^{-st} + t^2e^{-st} + d(t)e^{-st}) \, dt

Integrating, we have:

=> F(s) = (20.5\frac{e^{-st}}{s} - 10\frac{(t + 1)e^{-st}}{s^2} - \frac{(st(st + 2) + 2)e^{-st}}{s^3}  )\left \{ {{a} \atop {0}} \right.

Inputting the boundary conditions t = a = ∞, t = 0:

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F(s) = \int\limits^a_0 (e^{-t} + 4e^{-4t} + te^{-3t} )e^{-st} \, dt

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Integrating, we have:

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Inputting the boundary condition, t = a = ∞, t = 0:

F(s) = \frac{-1}{s + 1} - \frac{4}{s + 4} - \frac{4}{9(s + 1)^2}

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Answer:

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Answer:

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