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Pachacha [2.7K]
3 years ago
15

Which of these was designed to study Saturn?

Physics
2 answers:
Simora [160]3 years ago
5 0
<span>D) Voyager 1, Huygens, and Cassini,

Is the correct answer</span>
nataly862011 [7]3 years ago
4 0

The answer is D) Voyager 1, Huygens, and Cassini

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Why is venus called brightest star and mars called red planet​
bogdanovich [222]

Answer:given below by him is correct

Explanation:

Pls refer his

3 0
3 years ago
Which statement is true of convex mirrors?
Leno4ka [110]
I think it is d if not then im sorry
7 0
4 years ago
A current is established in a gas discharge tube when a sufficiently high potential difference is applied across the two electro
pishuonlain [190]

Explanation:

It is given that the number of electrons passing through the cross-sectional area in 1 s is 3.4 \times 10^{18}. Also, we know that charge on an electron is -1.60 \times 10^{-19} C, then negative charge crossing to the left per second is  as follows.

         I- = 3.4 \times 10^{18} electrons \times -1.6 x 10^{-19} C/electrons

         I- = 0.544 A

As it is given that the number of protons crossing per second is 1.4 \times 10^{18}, as the charge on the proton is +1.60 \times 10^{-19} C, then positive charge crossing to the right per second is calculated as follows.

          I+ = 1.4 \times 10^{18} electrons \times 1.6 \times 10^{-19} electrons/C

            I+ = 0.224 A

          I = l I+ l + l I- l

So,    I = 0.544 + 0.224

            = 0.768 A

Thus, we can conclude that the current in given hydrogen discharge tube is 0.768 A.

8 0
3 years ago
43- The lighter you are, the stronger the air resistance because:
expeople1 [14]

Answer:

b) The gravitational pull will be weak.

Explanation:

Less mass requires less force. Gravity or gravitational pull is a force. In order for you to stay in place and not go through the ground, however, you require something to pulling you away from the Earth. That's why we have air resistance.

5 0
3 years ago
Let’s look at a radio-controlled model car. Suppose that at time t1=2.0st1=2.0s the car has components of velocity vx=1.0m/svx=1
Nonamiya [84]

Answer:

a_x=6\ \text{m/s}^2 and a_y=0\ \text{m/s}^2

Magnitude of accleration is 6\ \text{m/s}^2 and the direction is 0^{\circ}

Explanation:

t_1=2\ \text{s}

v_x=1\ \text{m/s}

v_y=3\ \text{m/s}

t_2=2.5\ \text{s}

v_x=4\ \text{m/s}

v_y=3\ \text{m/s}

Average acceleration in the different axes

a_x=\dfrac{\Delta v_x}{\Delta t}\\\Rightarrow a_x=\dfrac{4-1}{2.5-2}\\\Rightarrow a_x=6\ \text{m/s}^2

a_y=\dfrac{\Delta v_y}{\Delta t}\\\Rightarrow a_y=\dfrac{3-3}{2.5-2}\\\Rightarrow a_y=0\ \text{m/s}^2

The components of the acceleration is a_x=6\ \text{m/s}^2 and a_y=0\ \text{m/s}^2

The magnitude of acceleration

a=\sqrt{a_x^2+a_y^2}\\\Rightarrow a=\sqrt{6^2+0^2}\\\Rightarrow a=6\ \text{m/s}^2

Direction

\theta=\tan^{-1}\dfrac{a_y}{a_x}\\\Rightarrow \theta=\tan^{-1}\dfrac{0}{6}\\\Rightarrow \theta=0^{\circ}

The magnitude of accleration is 6\ \text{m/s}^2 and the direction is 0^{\circ}.

7 0
3 years ago
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