A clarinetist, setting out for a performance, grabs his 3.230 kg3.230 kg clarinet case (including the clarinet) from the top of
1 answer:
You might be interested in
The term Freebody diagram refer to the diagram that could be drawn to show the forces that act on an object.
<h3>What is a freebody diagram?</h3>The term Freebody diagram refer to the diagram that could be drawn to show the forces that act on an object. We must note that the forces that act on a body determine the direction in which the body moves.
This is because, force is a vector quantity. As such the magnitude and direction of a force are both responsible when we are trying to determine the force that acts on the object.
Attached is the image of the upward motion of a vector that shows the forces that act on the vector. This is what we refer to as a Freebody diagram.
Learn more about freebody diagram:brainly.com/question/14390468
#SPJ1
Consult the attached free body diagram.
By Newton's second law, the net force on the crate acting parallel to the surface is
∑ F[para] = (370 N) cos(-20°) - f = 0
(this is the x-component of the resultant force)
where
• (370 N) cos(-20°) = magnitude of the horizontal component of the pushing force
• f = magnitude of kinetic friction
The crate is moving at a constant speed and thus not accelerating, so the crate is in equilibrium.
Solve for f :
f = (370 N) cos(-20°) ≈ 347.686 N
The net force acting perpendicular to the surface is
∑ F[perp] = n - 1480 N - (370 N) sin(-20°) = 0
(this is the y-component of the resultant force)
where
• n = magnitude of normal force
• 1480 N = weight of the crate
• (370 N) sin(-20°) = magnitude of the vertical component of push
The crate doesn't move up or down, so it's also in equilibrium in this direction.
Solve for n :
n = 1480 N + (370 N) sin(-20°) ≈ 1606.55 N ≈ 1610 N
Then the coefficient of kinetic friction is µ such that
f = µn ⇒ µ = f/n ≈ 0.216
