Answer:
Step-by-step explanation:
By MVT,
![4f'(c)= f(5) + 3\rightarrow f(5) = 4f'(c) - 3](https://tex.z-dn.net/?f=4f%27%28c%29%3D%20f%285%29%20%2B%203%5Crightarrow%20f%285%29%20%3D%204f%27%28c%29%20-%203)
Moreover, ![f'(x)\leq 4~~~~~~ \forall x,](https://tex.z-dn.net/?f=f%27%28x%29%5Cleq%204~~~~~~%20%5Cforall%20x%2C)
![f(5) \leq 16 - 3 =13](https://tex.z-dn.net/?f=f%285%29%20%5Cleq%2016%20-%203%20%3D13)
Hence the largest possible value of f(5) is 13
Answer: ![(-\infty, 7)](https://tex.z-dn.net/?f=%28-%5Cinfty%2C%207%29)
You can write this as (-infinity, 7) if you aren't able to use the infinity symbol.
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Explanation:
Think of x < 7 as writing ![-\infty < x < 7](https://tex.z-dn.net/?f=-%5Cinfty%20%3C%20x%20%3C%207)
So x is between negative infinity and 7, excluding both endpoints.
To write
in interval notation, we write
The curved parenthesis tell us to exclude the endpoint.
Seeing from the graph I've provided above, the correct answer would be D, the last one.
Answer:yu
Step-by-step explanation:
Answer:
Step-by-step explanation:
f(x)/g(x)=(6x+2)/(x-7)
The only restriction upon the domain, possible values of x, is division by zero is undefined. So x cannot equal 7.
So the domain is all real numbers except 7. In interval notation the domain is
x=(-oo, 7),(7, +oo)