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sasho [114]
3 years ago
15

A burst of electromagnetic radiation has a frequency of 1 exahertz. One exahertz equals 10^12 megahertz. Each megahertz is equal

to 10^6 hertz. What was the frequency of the burst of radiation in hertz? (^ indicates an exponent) *
Mathematics
1 answer:
den301095 [7]3 years ago
3 0

Answer:

The frequency of the burst of electromagnetic radiation which equals 1 exahertz = 10¹⁸ hertz.

Step-by-step explanation:

Since the frequency of the burst of electromagnetic radiation is 1 exahertz, and 1 exahertz = 10¹² megahertz. So, the frequency of radiation is 10¹² megahertz. Also 1 megahertz = 10⁶ hertz. So, 10¹² megahertz = 10¹² × 1 megahertz = 10¹² × 10⁶ hertz = 10¹² ⁺ ⁶ hertz = 10¹⁸ hertz.

So the frequency of the burst of electromagnetic radiation which equals 1 exahertz = 10¹⁸ hertz.

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Daniel's yard is perfectly rectangular. It has a length of 28 yards and a perimeter of 88 yards. Find the width of his yard.
Digiron [165]

Draw a picture of the yard, rectangle. On the two long sides, write 28 yards and on the two shorter ones, just write a question mark.

To figure out perimeter, you need to add up each side.

P = Perimeter

L = Length

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P = L(2) + W(2)

If the length is 28, double it. = 56

Now subtract that from the perimeter - 88-56=32

32 is what you have left, so now split that, and replace the question marks.

All-in-all each width is 16 yards, while each length is 28, making the whole rectangle have a perimeter of 88 yards.

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3 years ago
A pitcher contains a liquid mixture of water and lemon juice. The water makes up 2/5 of the weight of the liquid mixture. There
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Answer:

37.5

Step-by-step explanation:

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8 0
2 years ago
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3 years ago
The proprietor of Midland Construction Company has to decide between two projects. He estimates that the first project will yiel
Colt1911 [192]

Answer: Expected profit for first and second project are $158000 and $185000 respectively.

Step-by-step explanation:

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0.7      $170000

0.3      $130000

So, Expected profit would be

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Second project:

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E[x]=\sum xp(x)=0.7\times 230000+0.3\times 80000=\$185000

Hence, expected profit for first and second project are $158000 and $185000 respectively.

7 0
3 years ago
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