It is the right triangle so add up to 90
==> 90-65 = 25
Draw a picture of the yard, rectangle. On the two long sides, write 28 yards and on the two shorter ones, just write a question mark.
To figure out perimeter, you need to add up each side.
P = Perimeter
L = Length
W = Width
P = L(2) + W(2)
If the length is 28, double it. = 56
Now subtract that from the perimeter - 88-56=32
32 is what you have left, so now split that, and replace the question marks.
All-in-all each width is 16 yards, while each length is 28, making the whole rectangle have a perimeter of 88 yards.
Answer:
37.5
Step-by-step explanation:
25÷ 2 is 12.5
so 1/5 of the pitcher is 12.5 ounces
theres 3/5 left to fill in the pitcher
so the answer is 12.5 x 3 which is
37.5
Basically substitute y into the first equation: 2x+8(2)=20 and solve. Then plug in x to the second equation etc.
Answer: Expected profit for first and second project are $158000 and $185000 respectively.
Step-by-step explanation:
Since we have given that
First project :
a profit of $170,000 with a probability of 0.7 or a profit of $130,000 with a probability of 0.3
0.7 $170000
0.3 $130000
So, Expected profit would be
![E[x]=\sum xp(x)=0.7\times 170000+0.3\times 130000=\$158000](https://tex.z-dn.net/?f=E%5Bx%5D%3D%5Csum%20xp%28x%29%3D0.7%5Ctimes%20170000%2B0.3%5Ctimes%20130000%3D%5C%24158000)
Second project:
a profit of $230,000 with a probability of 0.7 or a profit of$80,000 with a probability of 0.3.
0.7 $230000
0.3 $80000
So, Expected profit would be
![E[x]=\sum xp(x)=0.7\times 230000+0.3\times 80000=\$185000](https://tex.z-dn.net/?f=E%5Bx%5D%3D%5Csum%20xp%28x%29%3D0.7%5Ctimes%20230000%2B0.3%5Ctimes%2080000%3D%5C%24185000)
Hence, expected profit for first and second project are $158000 and $185000 respectively.