Two angles are said to be complementary, if the sum of the measures of the to angles is equal to 90 degrees.
Thus, given that HFG is complementary to ACB, them mHFG + mACB = 90 degrees.
From the figure, given that the line from point F meats line CE at point P, then HFG = CFP.
But mCFE = 90 degrees and mCFE = mCFP + mPFE
Also PFE = DFH
Thus, mCFE = mCFP + mPFE = mHFG + mDFH = 90 degrees
Recall that mHFG + mACB = 90 degrees
Thus, mHFG + mACB = mHFG + mDFH
Therefore, mACB = mDFH.
I think this is the Domain. Since a domain is a group of numbers that can be entered in a function to create a valid output. They are set of all possible values of x which will satisfy a ffunction and output real y-values
25 anything raised to zero equals one
1. cylinder to cone:
(πr^2h)/((1/3)πr^2h) = 3:1
2. sphere to cylinder:
((4/3)πr^3)/(πr^2h) = 4r:3h
3. cone to sphere:
((1/3)πr^2h)/((4/3)πr^3) = h:4r
4. hemisphere to cylinder:
half the ratio of sphere to cylinder = 2r:3h
