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4 years ago

There are 180 cars in a parking lot. 45% are blue . How many blue cars are there?

Mathematics

2 answers:

Neko [114]4 years ago

7 0

Answer:

Step-by-step explanation first step 180-45 = 135 . 135 percent blue cars

swat324 years ago

3 0

There are 36 blue cars because 40% of 180 is 36

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THE GREATEST PRODUCT

Alex17521 [72]

Answer:

7*6543=45801

Step-by-step explanation:

We have the digits 34567 and must arrange them into a product with the largest possible value.

It's clear that we must place the largest digits to the left, so they represent larger numbers to multiply.

Let's try with:

7654*3=22962

765*43=32895

76*543=41268

7*6543=45801

This last combination definitely produces the largest product

Answer: 7*6543=45801

5 0

3 years ago

Use the points (2,-5) and (-1,4) and determine the slope using the slope formula

Rama09 [41]

(2,-5),(-1,4)
slope = (4 - (-5) / (-1 - 2) = (4 + 5) / -3 = -9/3 = -3 <==

6 0

3 years ago

The least common multiple of two numbers is 3780, and the greatest common divisor is 18. given that one of the numbers is 180, w

garri49 [273]

To solve these GCF and LCM problems, factor the numbers you're working with into primes:
3780 = 2*2*3*3*3*5*7
180 = 2*2*3*3*5
We know that the LCM of the two numbers, call them A and B, = 3780 and that A = 180. The greatest common factor of 180 and B = 18 so B has factors 2*3*3 in common with 180 but no other factors in common with 180. So, B has no more 2's and no 5's
Now, LCM(180,B) = 3780. So, A or B must have each of the factors of 3780. B needs another factor of 3 and a factor of 7 since LCM(A,B) needs for either A or B to have a factor of 2*2, which A has, and a factor of 3*3*3, which B will have with another factor of 3, and a factor of 7, which B will have.
So, B = 2*3*3*3*7 = 378.

8 0

3 years ago

41 kilometers to meter

g100num [7]

Answer:

41000 meters

Step-by-step explanation:

multiply the length value by 1000

4 0

3 years ago

Read 2 more answers

A financial advisor is analyzing a family's estate plan. The amount of money that the family has invested in different real esta

Pachacha [2.7K]

Answer:

The amount of money separating the lowest 80% of the amount invested from the highest 20% in a sampling distribution of 10 of the family's real estate holdings is $238,281.57.

Step-by-step explanation:

Let the random variable X represent the amount of money that the family has invested in different real estate properties.

The random variable X follows a Normal distribution with parameters μ = $225,000 and σ = $50,000.

It is provided that the family has invested in n = 10 different real estate properties.

Then the mean and standard deviation of amount of money that the family has invested in these 10 different real estate properties is:

$\mu_{\bar x}=\mu=\$225,000\\\\\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{50000}{\sqrt{10}}=15811.39$

Now the lowest 80% of the amount invested can be represented as follows:

$P(\bar X$

The value of z is 0.84.

*Use a z-table.

Compute the value of the mean amount invested as follows:

$\bar x=\mu_{\bar x}+z\cdot \sigma_{\bar x}$

$=225000+(0.84\times 15811.39)\\\\=225000+13281.5676\\\\=238281.5676\\\\\approx 238281.57$

Thus, the amount of money separating the lowest 80% of the amount invested from the highest 20% in a sampling distribution of 10 of the family's real estate holdings is $238,281.57.

6 0

3 years ago