Question

What are the solutions of the quadratic equation p^2+3p-28=40

Answer 1

Answer:

the answer is  =-3±$\sqrt{281}$/2

Step-by-step explanation:

Answer 2

Answer:

             $\bold{p_1\approx6.88\ ,\qquad p_2\approx-9.88}$

Step-by-step explanation:

$p^2+3p-28=40\\\\p^2+3p-68=0\\\\a=1\,,\ b=3\,,\ c=-68\\\\\\p=\dfrac{-3\pm\sqrt{3^2-4\cdot1\cdot(-68)}}{2\cdot1}=\dfrac{-3\pm\sqrt{281}}{2}\\\\p_1\approx6.88\ ,\qquad p_2\approx-9.88$