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3 years ago

What are the solutions of the quadratic equation p^2+3p-28=40

Mathematics

2 answers:

vivado [14]3 years ago

3 0

Answer:

the answer is =-3± $\sqrt{281}$ /2

Step-by-step explanation:

fgiga [73]3 years ago

3 0

Answer:

$\bold{p_1\approx6.88\ ,\qquad p_2\approx-9.88}$

Step-by-step explanation:

$p^2+3p-28=40\\\\p^2+3p-68=0\\\\a=1\,,\ b=3\,,\ c=-68\\\\\\p=\dfrac{-3\pm\sqrt{3^2-4\cdot1\cdot(-68)}}{2\cdot1}=\dfrac{-3\pm\sqrt{281}}{2}\\\\p_1\approx6.88\ ,\qquad p_2\approx-9.88$

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