Answer:
-14
Step-by-step explanation:
absolute value is just the number disregarding whether it's positive or negative, and the only even number less than -12 that is still under -15 is -14
Answer:
(a) The average baggage-related revenue per passenger is $15.70.
(b) The standard deviation of baggage-related revenue is $19.95.
(c) The expected revenue for 120 passengers is $1,884.
Step-by-step explanation:
Let the random variable <em>X</em> represent the baggage-related revenue per passenger.
It is provided that the baggage fees is $25 for the first bag and $35 for the second.
The probability model is:
X : 0 25 60
P (X) : 0.54 0.34 0.12
(a)
Compute the average baggage-related revenue per passenger as follows:


Thus, the average baggage-related revenue per passenger is $15.70.
(b)
Compute the standard deviation of baggage-related revenue as follows:



Thus, the standard deviation of baggage-related revenue is $19.95.
(c)
Compute the expected revenue for 120 passengers as follows:


Thus, the expected revenue for 120 passengers is $1,884.
Answer:
Answer:
<u>X l Y</u>
<u>-2 l 4</u>
<u>-1 l 5</u>
<u>0</u><u> </u><u> </u><u> </u><u> </u><u> </u><u>l</u><u> </u><u> </u><u> </u><u>6</u>
<u>1 l 7</u>
<u>2 l 8</u>
Step-by-step explanation:
<u>X </u><u> </u><u>l </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u>Y</u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>
<u>-2 l </u><u>-</u><u> </u><u>(</u><u>-</u><u>2</u><u>)</u><u> </u><u>+</u><u> </u><u>y</u><u> </u><u>=</u><u>6</u><u> </u><u>=</u><u>></u><u> </u><u>y</u><u> </u><u>=</u><u> </u><u>6</u><u> </u><u>-</u><u> </u><u>2</u><u>=</u><u>></u><u> </u><em><u>y</u><u> </u><u>=</u><u> </u><u>4</u></em>
<u>-1 l </u><u>- (-</u><u>1</u><u>) + y =6 => y = 6 - </u><u>1</u><u>=> <em>y = </em></u><u>5</u>
<u>0 l </u><u>- (</u><u>0</u><u>) + y =6 => y = 6 </u><u>+</u><u> </u><u>0</u><u>=> <em>y = </em></u><u>6</u>
<u>1 l </u><u>- (</u><u>1</u><u>) + y =6 => y = 6 </u><u>+</u><u>1</u><u> => <em>y = </em></u><u>7</u>
<u>2 l </u><u>- (</u><u>2</u><u>) + y =6 => y = 6 </u><u>+</u><u> 2=> <em>y = </em></u><u>8</u>
<em><u>Note</u></em><em><u>:</u></em><em><u> </u></em><em><u>-</u></em><em><u> </u></em><em><u>(</u></em><em><u>-</u></em><em><u>a</u></em><em><u>)</u></em><em><u> </u></em><em><u>+</u></em><em><u> </u></em><em><u>b</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>+</u></em><em><u> </u></em><em><u>b</u></em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em><u> </u></em><em><u>-</u></em><em><u> </u></em><em><u>(</u></em><em><u>a</u></em><em><u>)</u></em><em><u> </u></em><em><u>+</u></em><em><u> </u></em><em><u>b</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>-</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>+</u></em><em><u> </u></em><em><u>b</u></em>
when multiplying two binomials together we use the F.O.I.L. method:
First
Outer
Inner
Last
(7-3i)(2-i)
First: 7 * 2 ..... Outter: 7 * -i .... Inner: -3i * 2 ...... Last: -3i * -i
First: 14 ...... Outter= -7i ..... Inner: -6i .... Last: 3i^2
putting this together we get 14-7i-6i+2i^2
We combine like terms and end up with 2i^2-13i+14