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Vadim26 [7]
3 years ago
12

Talia tossed a penny many times. She got 30 heads and 70 tails. She said the experimental probability of getting heads was 30 70

. Explain and correct her error by completing the sentence. Enter your answer as a simplified fraction. She did not 30 and 70 to find the total number of trials. The experimental probability of landing on heads is
Mathematics
1 answer:
-BARSIC- [3]3 years ago
4 0

Answer:

The experimental probability of landing on heads is 0.3

Step-by-step explanation:

We are given the following in the question:

Number of heads = 30

Number of tails = 70

Talia said the probability of getting heads is \frac{30}{70}.

She evaluated the wrong probability.

She did not considered total number of trials in the experiment.

Formula for probability:

\text{Probability} = \displaystyle\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}

Probability of heads =

P(H) = \dfrac{30}{30+70} = \dfrac{30}{100} =0.3

The experimental probability of landing on heads is 0.3

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The number is even, the number is less than -12, and the absolute value of the number is between 9 and 15?
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Answer:

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Step-by-step explanation:

absolute value is just the number disregarding whether it's positive or negative, and the only even number less than -12 that is still under -15 is -14

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Which pair of triangles can be proven congruent by SAS? 2 identical triangles are shown. The triangle is reflected across a line
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Read 2 more answers
An airline charges the following baggage fees: $25 for the first bag and $35 for the second. Suppose 54% of passengers have no c
Triss [41]

Answer:

(a) The average baggage-related revenue per passenger is $15.70.

(b) The standard deviation of baggage-related revenue is $19.95.

(c) The expected revenue for 120 passengers is $1,884.

Step-by-step explanation:

Let the random variable <em>X</em> represent the baggage-related revenue per passenger.

It is provided that the baggage fees is $25 for the first bag and $35 for the second.

The probability model is:

    X :   0         25      60

P (X) : 0.54    0.34    0.12

(a)

Compute the average baggage-related revenue per passenger as follows:

E(X)=\sum {X\times P (X)}

         =(0\times 0.54)+(25\times 0.34)+(60\times 0.12)\\\\=0+8.50+7.20\\\\=15.70

Thus, the average baggage-related revenue per passenger is $15.70.

(b)

Compute the standard deviation of baggage-related revenue as follows:

E (X^{2})=\sum X^{2}\times P(X)}\\\\=(0^{2}\times 0.54)+(25^{2}\times 0.34)+(60^{2}\times 0.12)\\\\=0+212.50+432\\\\=644.5\\

SD(X)=\sqrt{E(X^{2})-(E(X))^{2}}

           =\sqrt{644.5-(15.7)^{2}}\\\\=19.950188\\\\\approx 19.95

Thus, the standard deviation of baggage-related revenue is $19.95.

(c)

Compute the expected revenue for 120 passengers as follows:

E(R)=n\times E(X)

        =120\times 15.7\\\\=1884

Thus, the expected revenue for 120 passengers is $1,884.

8 0
4 years ago
Complete the table of values to find the solutions of the equation -x + y = 6.
Korolek [52]

Answer:

Answer:

<u>X l Y</u>

<u>-2 l 4</u>

<u>-1 l 5</u>

<u>0</u><u> </u><u> </u><u> </u><u> </u><u> </u><u>l</u><u> </u><u> </u><u> </u><u>6</u>

<u>1 l 7</u>

<u>2 l 8</u>

Step-by-step explanation:

<u>X </u><u> </u><u>l </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u>Y</u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>

<u>-2 l </u><u>-</u><u> </u><u>(</u><u>-</u><u>2</u><u>)</u><u> </u><u>+</u><u> </u><u>y</u><u> </u><u>=</u><u>6</u><u> </u><u>=</u><u>></u><u> </u><u>y</u><u> </u><u>=</u><u> </u><u>6</u><u> </u><u>-</u><u> </u><u>2</u><u>=</u><u>></u><u> </u><em><u>y</u><u> </u><u>=</u><u> </u><u>4</u></em>

<u>-1 l </u><u>- (-</u><u>1</u><u>) + y =6 => y = 6 - </u><u>1</u><u>=> <em>y = </em></u><u>5</u>

<u>0 l </u><u>- (</u><u>0</u><u>) + y =6 => y = 6 </u><u>+</u><u> </u><u>0</u><u>=> <em>y = </em></u><u>6</u>

<u>1 l </u><u>- (</u><u>1</u><u>) + y =6 => y = 6 </u><u>+</u><u>1</u><u> => <em>y = </em></u><u>7</u>

<u>2 l </u><u>- (</u><u>2</u><u>) + y =6 => y = 6 </u><u>+</u><u> 2=> <em>y = </em></u><u>8</u>

<em><u>Note</u></em><em><u>:</u></em><em><u> </u></em><em><u>-</u></em><em><u> </u></em><em><u>(</u></em><em><u>-</u></em><em><u>a</u></em><em><u>)</u></em><em><u> </u></em><em><u>+</u></em><em><u> </u></em><em><u>b</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>+</u></em><em><u> </u></em><em><u>b</u></em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em><u> </u></em><em><u>-</u></em><em><u> </u></em><em><u>(</u></em><em><u>a</u></em><em><u>)</u></em><em><u> </u></em><em><u>+</u></em><em><u> </u></em><em><u>b</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>-</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>+</u></em><em><u> </u></em><em><u>b</u></em>

6 0
3 years ago
Simplify the given expression below: (7-3i)•(2-i)
Dimas [21]

when multiplying two binomials together we use the F.O.I.L. method:

First

Outer

Inner

Last

(7-3i)(2-i)

First: 7 * 2 ..... Outter: 7 * -i .... Inner: -3i * 2 ...... Last: -3i * -i

First: 14 ...... Outter= -7i ..... Inner: -6i .... Last: 3i^2

putting this together we get 14-7i-6i+2i^2

We combine like terms and end up with 2i^2-13i+14

5 0
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