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3 years ago

An arc length is a fractional part of the

Mathematics

1 answer:

LenaWriter [7]3 years ago

4 0

Answer:

Each of the 4 sectors have an area:

πR²/8 - πr²/8, where
R = 28/2 - 2 = 12 in
r = 6/2 = 3 in

Find the area:

A = π/8(12² - 3² ≈ 53 in²

Outer perimeter of the frame:

P = d + πd/2 =28( 1 + π/2) ≈ 72 in

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What is (1.2 x 10^-2) x (3 x 10^5)

liraira [26]

Answer:

B. 3.6 x 10^3

Step-by-step explanation:

(1.2 x 10^-2) x (3 x 10^5)

When we multiply terms with powers , we multiply the factors out front and add the exponents

a * 10^b * c* 10^d = ac * 10^(b+d)

(1.2 x 10^-2) x (3 x 10^5) = (1.2* 3) * 10^(-2+5)

= 3.6 * 10 ^3

6 0

3 years ago

Factorise x^2-3x+10=0

Mila [183]

(x-5)(x+2)=0
roots: x=5 and x= -2
see attached photo for steps

6 0

3 years ago

Read 2 more answers

Use a net to find the surface area of the cone to the nearest square centimeter. Use 3.14 for pi (Round to nearest whole number)

Mariana [72]

Given:

The radius of the base of the given cone = 5 cm

The slant height of the cone = 19 cm

To find the surface area of the given cone.

Formula

The surface area pf the given cone is,

where, r be the radius and

l be the slant height.

Now,

Taking, r = 5, l = 19 and π = 3.14 we get,

sq cm

or, sq cm

Rounding off to the nearest square centimeter, we get;

Hence,

The surface area of the cone is 377 sq cm.

3 0

3 years ago

In ΔWXY, x = 1.2 inches, y = 3.1 inches and ∠W=131°. Find ∠X, to the nearest 10th of an degree.

Oxana [17]

Answer:

13.1

Step-by-step explanation:.

6 0

3 years ago

Quadrilateral ABCD ABCD is similar to quadrilateral EFGH EFGH. The lengths of the three longest sides in quadrilateral ABCD ABCD

Kay [80]

Sketch the two quadrilaterals and label them as shown in the figure below.

Let x = length of the 4th side of ABCD.

Because ABCD ~ EFGH, therefore
x/5 = 14/6

That is,
x = (5/6)*14 = 11.67 ft

Answer: D. 11.7 ft

5 0

4 years ago