Analyzing a Reflection

Mathematics

1 answer:

babunello [35]3 years ago

7 0

Answer:

The x-coordinate changes

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dimaraw [331]

Answer:

Step-by-step explanation:

Simplify the following:

(-(2 + 2/3))/(-(1 + 1/3))

(-(2 + 2/3))/(-(1 + 1/3)) = (-1)/(-1)×(2 + 2/3)/(1 + 1/3) = (2 + 2/3)/(1 + 1/3):

(2 + 2/3)/(1 + 1/3)

Put 1 + 1/3 over the common denominator 3. 1 + 1/3 = 3/3 + 1/3:

(2 + 2/3)/(3/3 + 1/3)

3/3 + 1/3 = (3 + 1)/3:

(2 + 2/3)/((3 + 1)/3)

3 + 1 = 4:

(2 + 2/3)/(4/3)

Put 2 + 2/3 over the common denominator 3. 2 + 2/3 = (3×2)/3 + 2/3:

((3×2)/3 + 2/3)/(4/3)

3×2 = 6:

(6/3 + 2/3)/(4/3)

6/3 + 2/3 = (6 + 2)/3:

((6 + 2)/3)/(4/3)

6 + 2 = 8:

(8/3)/(4/3)

Multiply the numerator by the reciprocal of the denominator, (8/3)/(4/3) = 8/3×3/4:

(8×3)/(3×4)

(8×3)/(3×4) = 3/3×8/4 = 8/4:

8/4

The gcd of 8 and 4 is 4, so 8/4 = (4×2)/(4×1) = 4/4×2 = 2:

Answer: 2

7 0

3 years ago

Read 2 more answers

(PLEASE HELP BRO THIS IS DUE TMR)

Sonbull [250]

Answer:

Hold on, our servers are swamped. Wait for your answer to fully load.

more ponits not fair

Step-by-step explanation:

jus beig ismapHold on, our servers are swamped. Wait for your answer to fully load.

6 0

2 years ago

I am doing online class and I am looking for a little help please

kati45 [8]

The domain is about how far left-to-right the graph goes.
In relation to the x-axis, the graph starts at x = –3 (with an open circle at –3) and then continues over to the right forever.
This is the shown in the picture with the red markup.
In interval notation, this is (-3, infinity).

Remember to use that left-to-right orientation for interval notation!

The range is in turn about how low to how high the graph goes.
On the graph, I’d do the same thing I did on the red marked up graph and compare the graph to the y-axis.
The graph starts down at y = –5 (with an open circle at –5) and then continues on up forever.
In interval notation, this is (-5, infinity).