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2 years ago

Find the missing dimensions of each triangle described. height 14 in. area: 245 in2

Mathematics

1 answer:

Gemiola [76]2 years ago

7 0

$A= \frac{1}{2}bh$
$b= \frac{2A}{h}= \frac{2(245)}{14}=35$

The base of the triangle is 35 in.

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3 years ago

Point b has coordinates (-8,15) and lies on the circle whose equation is x^2+y^2=289. If an angles is drawn in standard position

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Answer:

$\cos \theta=-\dfrac{8}{17}$

Step-by-step explanation:

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Comparing with the general form a circle with center at the origin: $x^2+y^2=r^2$

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Therefore, the angle is in Quadrant II.

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