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3 years ago

Twenty students ride on a bus. two-fifths pack there lunches. how many of the students pack their lunch

Mathematics

2 answers:

Volgvan3 years ago

8 0

Answer: The answer is 8 students.

Step-by-step explanation: Given that there is a bus full of students in which the total number of students is 20.

Also, it is given that two-fifth of the students pack their lunches.

So, the number of students who pack their lunches is given by

$n=\dfrac{2}{5}~\textup{of the total number of students}=\dfrac{2}{5}\times 20=2\times 4=8.$

Thus, the number of students who pack their lunches is 8.

Travka [436]3 years ago

5 0

$\frac{2}{5} \times 20 = 8$

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2 years ago

You bought a large container of fruit punch. The label on the container says there are 128fluid ounces of fruit punch in the con

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Answer:

16 cups.

Step-by-step explanation:

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3 years ago

Last month Kim trained 3 times as many dogs as cats.

Lisa [10]

Answer:

Step-by-step explanation:

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6 0

2 years ago

Find the measure of an interior angle of a regular polygon with 6 sides. Round to the nearest tenth if necessary.

Andreyy89

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2 years ago

Will mark BRAINLIST for only correct answer

katovenus [111]

Answer:

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Step-by-step explanation:

A linear relationship is a relationship of the form y = mx + b, where y and x are the linear variables, m is the rate of change and b is the value of y when x = 0.

Gym A:

Let x represent the month and y represent the total cost for the gym. From the table, we can represent the values in the form (x, y) as (1,70), (2, 90) and (3, 110). We can find the relationship between x and y using the formula:

$y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)\\\\Let \ us\ use\ the\ points\ (1,70)\ and\ (3,110),hence:\\\\y-70=\frac{110-70}{3-1}(x-1)\\\\y-70=20(x-1)\\\\y=20x-20+70 \\\\y=20x+50\\\\For\ 10\ months(i.e.\ x=10):\\\\y=20x+50\\\\y=20(10)+50\\\\y=\$250$

Gym B:

We can represent the values from the table as (1,55), (2, 80) and (3, 105). We can find the relationship between x and y using the formula:

$y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)\\\\Let \ us\ use\ the\ points\ (1,55)\ and\ (3,105),hence:\\\\y-55=\frac{105-55}{3-1}(x-1)\\\\y-55=25(x-1)\\\\y=25x-25+55 \\\\y=25x+30\\\\For\ 10\ months(i.e.\ x=10):\\\\y=25x+30\\\\y=25(10)+30\\\\y=\$28 0$

Hence gym A would cost less ($250 < $280)

4 0

2 years ago