Which of the following is an example of qualitative data

4. Lydia cut out her initial from a piece<br><br> of construction paper,

Ratling [72]

Answer:

Option A is correct.

10 square centimeters.

Step-by-step explanation:

Complete Question

The complete Question is attached in the first attached image.

Lydia cut out her initial from a piece of construction paper. How many square centimeters of construction paper are used to make Lydia's initial?

A) 10 square centimeters

B) 11 square centimeters

C) 15 square centimeters

D) 22 square centimeters

Solution

From the second attached image, it is evident that we can split the L-shaped figure into two rectangles of dimensions (3 cm by 1 cm) and (7 cm by 1 cm)

The total area of the figure is thus

(3 × 1) + (7 × 1) = 10 cm²

Hope this Helps!!!

3 0

3 years ago

2. The electrical resistance R of a wire varies inversely with the square of its diameter d. If a wire with a

Mariulka [41]

Answer:

$0.225 \Omega =225 m\Omega$

Step-by-step explanation:

We know (Ohm second law) that $R= \frac{k}{d^2}$ where k inlcudes the rest of the parameters (material, lenght). In our situation we have k= $0.4\cdot9 \Omega mm^2$ . The moment the diameter becomes 8mm R becomes

$R= {{0.4\cdot 9}\over{16}} \Omega = 0.225 \Omega$

4 0

2 years ago

How many different outcomes are possible if you can choose between a bus or a train, full fare or concession and you can travel

Novosadov [1.4K]

3 pairs of choices give rise to 2^3 = 8 possibilities:
.. bus, full, morning
.. bus, full, afternoon
.. bus, concession, morning
.. bus, concession, afternoon
.. train, full, morning
.. train, full, afternoon
.. train, concession, morning
.. train, concession, afternoon

7 0

3 years ago

Evaluate the following integral using trigonometric substitution

serg [7]

Answer:

The result of the integral is:

$\arcsin{(\frac{x}{3})} + C$

Step-by-step explanation:

We are given the following integral:

$\int \frac{dx}{\sqrt{9-x^2}}$

Trigonometric substitution:

We have the term in the following format: $a^2 - x^2$ , in which a = 3.

In this case, the substitution is given by:

$x = a\sin{\theta}$

So

$dx = a\cos{\theta}d\theta$

In this question:

$a = 3$

$x = 3\sin{\theta}$

$dx = 3\cos{\theta}d\theta$

So

$\int \frac{3\cos{\theta}d\theta}{\sqrt{9-(3\sin{\theta})^2}} = \int \frac{3\cos{\theta}d\theta}{\sqrt{9 - 9\sin^{2}{\theta}}} = \int \frac{3\cos{\theta}d\theta}{\sqrt{9(1 - \sin^{\theta})}}$

We have the following trigonometric identity:

$\sin^{2}{\theta} + \cos^{2}{\theta} = 1$

So

$1 - \sin^{2}{\theta} = \cos^{2}{\theta}$

Replacing into the integral:

$\int \frac{3\cos{\theta}d\theta}{\sqrt{9(1 - \sin^{2}{\theta})}} = \int{\frac{3\cos{\theta}d\theta}{\sqrt{9\cos^{2}{\theta}}} = \int \frac{3\cos{\theta}d\theta}{3\cos{\theta}} = \int d\theta = \theta + C$