We have been given that in a circle an arc length 10 is intercepted by a central angle of 2/3. We are supposed to find the radius of the circle.
We will use arc-length formula to solve our given problem.
, where,
= Arc length,
= Radius,
= Central angle corresponding to arc length.
Upon substituting our given values in arc-length formula, we will get:
Therefore, the radius of the given circle would be 15 units.
Answer: No, we don't have a right triangle
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Explanation:
If a triangle with sides a,b,c makes the equation a^2+b^2 = c^2 true, where c is the longest side, then this triangle is a right triangle. This is the converse of the pythagorean theorem.
Here we have a = 2, b = 5 and c = 7.
So...
a^2+b^2 = c^2
2^2+5^2 = 7^2
4+25 = 49
29 = 49
The last equation is false, so the first equation is false for those a,b,c values. Therefore, we do <u>not</u> have a right triangle.
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In contrast, consider the classic 3-4-5 right triangle
a = 3, b = 4 and c = 5 would make a^2+b^2 = c^2 true because 3^2+4^2 = 5^2 is a true equation (both sides lead to 25).
Answer:
40
Step-by-step explanation:
40x5=200
200 divided by 5 =40
Answer:
No. It can be obtuse angle are angles greater than 90° but less than 180°
And for an isosceles triangle, two angles must be equal so if two angles are greater than 90° that mean the sum of angle in a triangle is above 180° which is not possible
Step-by-step explanation:
F
(
n
)
=
87 That’s Standard form
