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3 years ago

Need some help! With any of the questions

Mathematics

1 answer:

Vadim26 [7]3 years ago

8 0

Answer:

For 12 I think AB is 38

Step-by-step explanation:

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I AM IN A HURRY!!!!!

Butoxors [25]

Answer:

Step-by-step explanation:

Because 2 is greater than 3

3 0

2 years ago

The difference of x and 5 is less than 21.<br> Translate the sentence into an inequality.

Ad libitum [116K]

Answer:

x-5<21

Step-by-step explanation:

3 0

3 years ago

Which expression is equivalent to 4/5 divided by 8

notsponge [240]

4/5 divided by 8 is 0.1 other than that I don’t know that question is kind of vague

6 0

3 years ago

Find the complete factorization of the expression. 12xy + 28xz A) 4yz(10x) B) 4yz(3x + 7x) C) 4x(3y + 7z) D) 4(3xy + 7yz)

VashaNatasha [74]

Answer:

<em>The correct option is: C) 4x(3y + 7z)</em>

Step-by-step explanation:

Given expression is: $12xy+28xz$

First we need to find the GCF(Greatest common factor) of $12xy$ and $28xz$ and then we will factor out that GCF.

$12xy \Rightarrow 2\times 2\times 3\times x\times y\\ \\ 28xz\Rightarrow 2\times 2\times 7\times x\times z$

We can see that the common factors are: $2,2, x$

So, the GCF will be: $2\times 2\times x= 4x$

Now factoring out $4x$ from the given expression, we will get.....

$12xy+28xz\\ \\ = 4x(\frac{12xy}{4x}+ \frac{28xz}{4x}) \\ \\ =4x(3y+7z)$

So, the complete factorization will be: $4x(3y+7z)$

7 0

3 years ago

Find the solution set of the following quadratic equations using the quadratic formula.

oksian1 [2.3K]

Answer:

<h3> 1) $x_1=\dfrac{7+\sqrt{13}}2\,,\quad x_2=\dfrac{7-\sqrt{13}}2$ </h3><h3> 2) $x_1=-\dfrac13\,,\quad x_2=-3$ </h3>

Step-by-step explanation:

$x^2 - 7x + 9 = 0\quad\implies\quad a=1\,,\ b = -7\,,\ c=9\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}=\dfrac{-(-7)\pm\sqrt{(-7)^2-4\cdot1\cdot9}}{2\cdot1}=\dfrac{7\pm\sqrt{49-36}}2\\\\x_1=\dfrac{7+\sqrt{13}}2\,,\quad x_2=\dfrac{7-\sqrt{13}}2$

<h3>2)</h3><h3> $3x^2 + 10x=-3\\\\3x^2+10x+3=0\quad\implies\quad a=3\,,\ b =10\,,\ c=3\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}=\dfrac{-10\pm\sqrt{10^2-4\cdot3\cdot3}}{2\cdot3}= \dfrac{-10\pm\sqrt{100-36}}6\\\\x_1=\dfrac{-10+\sqrt{64}}6=\dfrac{-10+8}6=-\dfrac13\,,\qquad x_2=\dfrac{-10-8}6=-3$ </h3>

7 0

3 years ago