Answer:
2.33 Seconds
Step-by-step explanation:
The equation y = -6t^2 - 10t + 56 expresses the height of a ball at a given time, t, on the planet Mars. We are also given that the ball is thrown with a velocity of 10 feet per second with the initial height of 56 feet.
To find the amount of time to reach the ground, we can say that the time being found will be when the ball is on the ground, or when y = 0. So we simply set our equation to 0 and solve for t.
y = -6t^2 - 10t + 56
0 = -6t^2 - 10t + 56
0 = -1 (6t^2 + 10t + -56)
0 = -1 (3t - 7) (2t + 8)
(3t - 7) = 0 OR (2t + 8) = 0
3t = 7 OR 2t = -8
t = 7/3 OR t = -4
Since time will not be negative, we will want to choose the positive solution for this quadratic equation.
Hence, the amount of time for the ball to hit the ground will be 7/3 seconds or 2.33 seconds.
Cheers.
Step-by-step explanation:
step 1. break into 2 shapes: a rectangle of sides 3 and 4. a triangle of sides (x - 3), 4, and y.
step 2. y = 4sqrt(2) (definition of a 45° triangle)
step 3. note: sqrt is the square root.
step 4. x - 3 = 4 (definition of a 45° triangle)
step 5. x = 7 (add 3 to both sides).
Answer:
B
Step-by-step explanation:
equation of a line =
y-y1=m(x-x1)
where m is the gradient and X1 and y1 are the points on the line.
slope= gradient
<em>4=X, 1/3= y</em>
y-1/3 = 3/4 (x-4)
