Answer:
I did this before it is C
Step-by-step explanation:
Answer:
17. a)
Step-by-step explanation:
17.
f(x) =x/2, then f(x-3)=(x-3)/2
x=3, f(x-3)=f(3-3)=f(0)=0 (values in table)
f(x-3)+3=0+3=3
18.
f(x) =x/2
f(x-2) for x=5 is f(5-2)=f(3)=3/2
f(x-2)+5=f(3)+5=3/2+5=3/2+10/2=13/2
Answer:
I don't know what you are saying for solve for x though if your saying simplify
simplify answer: -9
If 2(3x-6) = 3 (2x-1) answer: No solution
If 2(3x-6) = -3 (2x-1) answer: x = 1.25
Step-by-step explanation:
The probability that both items will be Harry Potter themed is 1/8.
<u>Step-by-step explanation:</u>
Total Number of pajama pants n(P) =8
Total number of slippers n(S)= 3
Number of Harry Potter themed Pajama pants n(H.P)=3
Number of Harry Potter themed slippers n(H.S)=1
We have to determine the probability of selecting pants and slippers that are both Harry Potter themed.
If two events A and B are independent, then the probability of A and B is given by
P(A and B)=P(A)*P(B)
Here the events selecting Harry potter themed pants and selecting harry Potter themed slippers are independent.





Hence probability of selecting Harry potter themed pants and Harry potter themed slippers is 1/8