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ankoles [38]
3 years ago
5

What is the possible length of the unknown side of the triangle ?

Mathematics
1 answer:
Hitman42 [59]3 years ago
5 0

use the Pythagorean theorem to get 6x


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78 ÷ 8 is equivalent to 78.00 ÷ 8. We can write zeros in the tenths place and hundredths place without changing the value. Use t
ahrayia [7]

Answer: 9.75

Step-by-step explanation:

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3 years ago
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The solid was created by connecting two congruent square pyramids to a rectangular prism.
AnnyKZ [126]

Answer:

  1920 square inches

Step-by-step explanation:

For a rectangular prism, the lateral area can be found by ...

  LA = Pl

where P is the perimeter, and l is the length.

For a square pyramid, the lateral area can be found by ...

  LA = (1/2)Ph

where P is the perimeter of the base, and h is the slant height of the triangular faces.

For a figure with a square cross section of perimeter P "capped" by square pyramids on either end, the total surface area is the sum of the lateral areas of the three components:

  SA = (Pl) + (1/2)Ph + (1/2)Ph

  SA = P(l+h) = (4×15 in)(14 +18 in) = (60)(32) in²

  SA = 1920 in²

The surface area of the solid seems to be 1920 square inches.

__

<em>Caveat</em>

If the figure is something other than what we have tried to describe, your mileage may vary. A diagram would be helpful.

3 0
3 years ago
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(X,y) —&gt; (x,-y) rule
ch4aika [34]
Can you help me with math
5 0
3 years ago
What does x equal? 3(x-7)=138+3x
Arturiano [62]
3(x-7) = 138 + 3x      First multiply
3x-21 = 138 + 3x      subtract 3x from both sides 
-21 = 138            

This is a false statement because -21 does not equal to 138 so the answer is no solution.

Hope this helps! Please give me the brainliest answer if you like it! If you have further questions, please leave a comment or add me as a friend!
7 0
3 years ago
Evaluate the expression for the given values. 4ab Divided by 8c , where a = 8, b = 4, and c =12 Enter your answer in the box.
Aleks04 [339]
4ab / 8c

a=8
b=4
c=12

4 x 8 x 4 / 8 x 12 = 192

Hope this helped!!!
5 0
3 years ago
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