Answer:
Step-by-step explanation:
You read a graph from left to right, just like you would read words on a page in a book. At the left-most "side" of this graph, we are way up at positive infinity. As we move from left to right, the graph begins to drop in y values. A drop in y values indicates a decreasing graph. So it's decreasing, we have that part. As the graph grows up into y values that increase forever, it will also grow in the x direction to negative infinity. As the graph decreases in y values from left to right, the x values increase into positive infinity. So your choice is the second one: The function is decreasing on the interval (-∞, ∞).
by the double angle identity for sine. Move everything to one side and factor out the cosine term.
Now the zero product property tells us that there are two cases where this is true,
In the first equation, cosine becomes zero whenever its argument is an odd integer multiple of
, so
where
![n[/tex ]is any integer.\\Meanwhile,\\[tex]10\sin x-3=0\implies\sin x=\dfrac3{10}](https://tex.z-dn.net/?f=n%5B%2Ftex%20%5Dis%20any%20integer.%5C%5CMeanwhile%2C%5C%5C%5Btex%5D10%5Csin%20x-3%3D0%5Cimplies%5Csin%20x%3D%5Cdfrac3%7B10%7D)
which occurs twice in the interval
for
and
. More generally, if you think of
as a point on the unit circle, this occurs whenever
also completes a full revolution about the origin. This means for any integer
, the general solution in this case would be
and
.
The first 2 and last 2. I just did this assignment
The answer is:<span>
</span><span>
</span><span>= <span><span>2p</span>+<span>10</span></span></span>
