Answer:
2
Step-by-step explanation:
Since FG is congruent to FH, angles FGH and FHG are congruent since angles opposite congruent sides in a triangle are congruent.
Hello!
Answer:

To solve, we will need to use Right-Triangle Trigonometry:
Begin by solving for angles ∠S and ∠R using tangent (tan = opp/adj)
tan ∠S = a / (1/2b)
tan ∠S = 3√5 / 14
tan ∠S ≈ 0.479
arctan 0.479 = m∠S (inverse)
m∠S and m∠R ≈ 25.6°
Use cosine to solve for the hypotenuse, or the missing side-length:
cos ∠S = 14 / x
x · cos (25.6) = 14
x = 14 / cos(25.6)
x ≈ 15.52
Both triangles are congruent, so we can go ahead and find the perimeter of the figure:
RS + RQ + QS = 28 + 15.52 + 15.52 = 59.04 units.
Hope this helped you! :)
C.
y - 65 = -10(x - 6)
is what i say it is but im not for sure, so sry if im wrong.
301.6=3.14×4×h/3
301.6=12.56×h/3
3770/157=h/3
72 6/157=h. Hope it help!