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frozen [14]
3 years ago
12

PLEASE SHOW YOUR WORK!!! (solve system of equations by adding, subtracting, or multiplying.)

Mathematics
1 answer:
Aliun [14]3 years ago
5 0
Hey friend, hope I can assist you!
I will solve by elimination <3.
Multiply 3x - 7y = 2 by 2: 6x - 14y = 4
6x - 14y = 4
6x - 9y = 9
5y = 5
Now we have
6x - 14y = 4
5y = 5
Now we want to solve 5y = 5 for y
So simply divide both sides by 5.
5y/5 = 5/5
This gives us one or in other words, y = 1.
Now we want to plug y = 1 into  6x - 14y = 4
So 6x - 14 * 1 = 4
This gives us
6x - 14 = 4
Now add 14 to both sides.
6x - 14 + 14 = 4 + 14
6x = 18
Now divide both sides by 6
6x/6 = 18/6
This gives us 3 so x = 3
Therefore our solutions to this system of equations would be y = 1 and x = 3

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IRISSAK [1]
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Answer B
6 0
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A dormitory has 40 students---12 sophomores, 8 juniors, and 20 seniors. Which of the following is equal to the number of ways to
Maurinko [17]

Answer:

The number of ways is equal to 12!8!20!

Step-by-step explanation:

The multiplication principle states that If a first experiment can happen in n1 ways, then a second experiment can happen in n2 ways ... and finally a i-experiment can happen in ni ways therefore the total ways in which the whole experiment can occur are

n1 x n2 x ... x ni

Also, given n-elements in which we want to put them in a row, the total ways to do this are n! that is n-factorial.

For example : We want to put 4 different objects in a row.

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Using the multiplication principle and the n-factorial number :

The number of ways to put all 40 in a row for a picture, with all 12 sophomores on the left,all 8 juniors in the middle, and all 20 seniors on the right are : The total ways to put all 12 sophomores in a row multiply by the ways to put the 8 juniors in a row and finally multiply by the total ways to put all 20 senior in a row ⇒ 12!8!20!

4 0
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Arte-miy333 [17]

Answer:

isn't this physics? im sorry if it's not

4 0
4 years ago
Read 2 more answers
Will make you brainliest!!! If correct!!
Virty [35]

Answer:

Step-by-step explanation:

y = - \frac{1}{4} x + 3 ( equation of line t )

y - (- 2) = - \frac{1}{4} [ x - (- 2)] ⇒ y = - \frac{1}{4} x - \frac{5}{2} ( equation of line u )

5 0
3 years ago
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