If we let p and t be the masses of the paper and textbook, respectively, the equations that would best represent the given in this item are:
(1) 20p + 9t = 44.4
(2) (20 + 5)p + (9 + 1)t = 51
The values of p and t from the equation are 0.6 and 3.6, respectively. Thus, each paperback weighs 0.6 pounds and each textbook weighs 3.6 pounds.
It's easy it's just 62×9 it equals 558
Answer:
P=2x+2y+14
Step-by-step explanation:
Perimeter (P)of a rectangle = 2( l+b)
where l is the length and b is the width of the rectangle .
Here, l= x+8
and, b= y-1
so, P = 2{(x+8)+(y-1)}
= 2( x+8+y-1)
= 2(x+y+7)
=2x+2y+14
Answer:
Once
Step-by-step explanation:
8 can only go into 9 once, if you were to do it a second time, there would be a remainder of 7.
Answer:
18.288
Step-by-step explanation:
