Ask question

Ask question

All categories

vladimir1956 [14]

3 years ago

7

Mary and Roberto bought identical backpacks at different stores. Mary's backpack originally cost $65 and was discounted 25%. Rob

erto's backpack originally cost $75 and was on sale for 30% off of the original price. Which backpack was a better buy?

1 answer:

mihalych1998 [28]3 years ago

8 0

Answer:

Mary's

Step-by-step explanation:

You might be interested in

Solve the triangle m<N= 118°, m<P= 33° and m=15. Round to the nearest tenth. Please show work.

kirill [66]

Answer:

M = 29

27.31838095 = n

16.8511209 = p

Step-by-step explanation:

M = 180 -33-118 = 29

We can use the rule of sines

sin A sin B sin C

------------ = ---------- = ------------

a b c

sin 118 sin 29

------------ = ----------

n 15

Using cross products

15 sin 118 = n sin 29

Divide by sin 29

15 sin 118 / sin 29 = n

27.31838095 = n

sin 33 sin 29

------------ = ----------

p 15

Using cross products

15 sin 33 = p sin 29

Divide by sin 29

15 sin 33 / sin 29 = p

16.8511209 = p

3 0

3 years ago

Please help!! I’ll mark the correct answer as brainly

GenaCL600 [577]

The answer is B. There can not be any alike "x" inputs.

4 0

3 years ago

Read 2 more answers

Leo walks his dog 7/8 mile. He walks his dog 3 times a day. How far does Leo walk his dog every day? Show how you can use repeat

alexandr402 [8]

7/8 +7/8 + 7/8 = 21/8 or 2 5/8 miles

7 0

3 years ago

Use polar coordinates to find the volume of the given solid. Inside both the cylinder x2 y2 = 1 and the ellipsoid 4x2 4y2 z2 = 6

Anton [14]

The Volume of the given solid using polar coordinate is: $\frac{-1}{6} \int\limits^{2\pi}_ {0} [(60) ^{3/2} \; -(64) ^{3/2} ] d\theta$

V= $\frac{-1}{6} \int\limits^{2\pi}_ {0} [(60) ^{3/2} \; -(64) ^{3/2} ] d\theta$

<h3>What is Volume of Solid in polar coordinates?</h3>

To find the volume in polar coordinates bounded above by a surface z=f(r,θ) over a region on the xy-plane, use a double integral in polar coordinates.

Consider the cylinder, $x^{2}+y^{2} =1$ and the ellipsoid, $4x^{2}+ 4y^{2} + z^{2} =64$

In polar coordinates, we know that

$x^{2}+y^{2} =r^{2}$

So, the ellipsoid gives

$4{(x^{2}+ y^{2)} + z^{2} =64$

4( $r^{2}$ ) + $z^{2}$ = 64

$z^{2}$ = 64- 4( $r^{2}$ )

z=± $\sqrt{64-4r^{2} }$

So, the volume of the solid is given by:

V= $\int\limits^{2\pi}_ 0 \int\limits^1_0{} \, [\sqrt{64-4r^{2} }- (-\sqrt{64-4r^{2} })] r dr d\theta$

= $2\int\limits^{2\pi}_ 0 \int\limits^1_0 \, r\sqrt{64-4r^{2} } r dr d\theta$

To solve the integral take, $64-4r^{2}$ = t

dt= -8rdr

rdr = $\frac{-1}{8} dt$

So, the integral $\int\ r\sqrt{64-4r^{2} } rdr$ become

= $\int\ \sqrt{t } \frac{-1}{8} dt$

= $\frac{-1}{12} t^{3/2}$

= $\frac{-1}{12} (64-4r^{2}) ^{3/2}$

so on applying the limit, the volume becomes

V= $2\int\limits^{2\pi}_ {0} \int\limits^1_0{} \, \frac{-1}{12} (64-4r^{2}) ^{3/2} d\theta$

= $\frac{-1}{6} \int\limits^{2\pi}_ {0} [(64-4(1)^{2}) ^{3/2} \; -(64-4(2)^{0}) ^{3/2} ] d\theta$

V = $\frac{-1}{6} \int\limits^{2\pi}_ {0} [(60) ^{3/2} \; -(64) ^{3/2} ] d\theta$

Since, further the integral isn't having any term of $\theta$ .

we will end here.

The Volume of the given solid using polar coordinate is: $\frac{-1}{6} \int\limits^{2\pi}_ {0} [(60) ^{3/2} \; -(64) ^{3/2} ] d\theta$

Learn more about Volume in polar coordinate here:

brainly.com/question/25172004

#SPJ4

3 0

1 year ago

How many cubes with edge lengths of 1/4 in. will it take to fill the prism?

Ulleksa [173]

Answer:

1560

Step-by-step explanation:

First (2 1/2)/(1/4) = (5/2)(4) = 20/2 = 10

Next, 3/(1/4) = 3(4) = 12

Lastly, (3 1/4)/(1/4) = (13/4) x 4 = 52/4 = 13

This means we need 10 rows of 12, 13 high. 10(12)(13) = 1560 cubes.

Another way is to multiply 2 1/2 x 3 x 3 1/4 = 5/2 x 3 x 13/4 = 195/8

A 1/4 inch cube is 1/4 x 1/4 x 1/4 for a volume of 1/64

(195/8)/(1/64) = (195/8)(64) = 1560 cubes.

3 0

2 years ago