-9 < 2
-1 > -3
0 < 6
a < b = a is less than b
a > b = a is greater than b
Answer:
8.20 am
Step-by-step explanation:
First, we have that Bus A will be back after 20 minutes, then after 40, then 60, 80, 100, 120, <u>140</u>, 160 minutes, etc.
Then, we have that Bus B will be back after 35 minutes, then 70, then 105, then <u>140</u>, 175....
From the list above we see that the first time they are both back at the station is after 140 minutes. (it's the MCM).
If we express this in terms of minutes, since one hour has 60 minutes, 2 hours have 120 minutes and thus, 140 minutes is 2 hours and 20 minutes.
Therefore, they will be both back at the station 2 hours and 20 minutes after they first departed at 6 am, so they will be back at the depot at 8.20 am
Answer:
Therefore (2.30-0.03747)= 2.2625 M of HI remains from an initial concentration of 2.30 M after 4.5 hours.
Step-by-step explanation:
second order reaction: The rate of reaction proportional to the square of the concentration of reactant.
For second order reaction
K is rate constant = 1.6×10⁻³M⁻¹hr⁻¹
a = initial concentration of reactant = 2.30 M
a-x = concentration of reactant after t h
t = time = 4.5 h
Putting the values in the above equation,
Therefore (2.30-0.03747)= 2.2625 M of HI remains from an initial concentration of 2.30 M after 4.5 hours.
Answer:
8. 2/7 9. 3/4 10. 3/5
Step-by-step explanation:
simplify 4/14 by 2, simplify 15/20 by 5, and simplify 21/35 by 7, hope this helps