To factor quadratic equations of the form ax^2+bx+c=y, you must find two values, j and k, which satisfy two conditions.
jk=ac and j+k=b
The you replace the single linear term bx with jx and kx. Finally then you factor the first pair of terms and the second pair of terms. In this problem...
2k^2-5k-18=0
2k^2+4k-9k-18=0
2k(k+2)-9(k+2)=0
(2k-9)(k+2)=0
so k=-2 and 9/2
k=(-2, 4.5)
I could be wrong, but I'm pretty sure here the answer would be 10x^2 + 17x +3 would be the area since you have to multiply length and width. since these are expressions with no answers and no other numbers, we can't find x.
6x=-5y
-5y=6x
so the answer is y=-6/5x
Yes you have the correct one good job.
Answer:
The third or bottom left option.
Step-by-step explanation:
Pay attention to the slopes. If it is negative that the graph points to the top left or bottom right and the opposite for a positive slope(slope is the coefficient of the x value meaning if the slope is a very small negative number or a large positive number than the steepness changes) This can be solved purely through the process of elimination which is how I did it.
