1.) 44
2.) 29
3.) 27
4.) 18
5.) 37
6.) 24
7.) 42
8.) 506
9.) 0
10.) -5
Answer:
1/6
Step-by-step explanation:
Well perpendicular lines are reciprocals of each other,
meaning if like k has a slope of -6 then line n will have a slope of positive 1/6.
<em>Thus,</em>
<em>line n has a slope of 1/6.</em>
<em />
<em>Hope this helps:)</em>
Answer:
answer 60
Step-by-step explanation:
The LCM(12, 20) = 60.
If
and
, separate variables in the differential equation to get

Integrate both sides:

Use the initial condition to solve for
:

Then the particular solution to the initial value problem is

(A)