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sp2606 [1]
3 years ago
15

A similarity transformation maps polygon ABCD to polygon PORS. If the length of AB is 6 and the length of the corresponding side

. PO, is 12.
what is the scale factor of dilation?
A 2
B. 0.5
oc 6
D. 6
Mathematics
2 answers:
Assoli18 [71]3 years ago
8 0
The correct answer to this question is 2 whitch is letter answer A
joja [24]3 years ago
4 0

Answer:

Scale factor = 2

Step-by-step explanation:

Scale factors deal multiplication. So, you would need to find a number to multiply by 6 to get 12. You can do this by doing 12 / 6.

12 / 6 = 2

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Rolls are being prepared to go to grocery stores. Divide 72 rolls into 2 groups so the ratio is 3 to 5. (please include your wor
natali 33 [55]
\sf 3:5 \to 3x:5x\\\\3x +5 = 8x\\ 8x = 72\\ x = 9\\\\9\times 3 =27\\9\times 5 =45\\ 27+45=72\\\\so~ the~ 2~ groups ~are~ 27~ and~ 45
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3 years ago
What is 3x squared-12x=0
lubasha [3.4K]

x=0 or x=4

just factorize basically

cancels the x’s so it’d be 3x-12=0 and from that x=4

3 0
4 years ago
PLEASE HELP NEED NOW!!!
ddd [48]
If the number of adult tickets are taken as x then the number of children’s tickets can be taken as (89 — x ) then we can set up the equation

4.10(x) + 2.70 (89 — x) = 331.30
4.10x + 240.3 — 2.70x = 331.30
1.4x = 331.30 — 240.30
1.4x = 91
X = 65

Therefore 65 adult tickets and 24 children tickets as 89 — 65 is 24
5 0
3 years ago
a math teacher claims that she has developed a review course that increases the score of students on the math portion of a colle
madam [21]

Answer:

A.

H_0: \mu\leq514\\\\H_1: \mu>514

B. Z=2.255. P=0.01207.

C. Although it is not big difference, it is an improvement that has evidence. The scores are expected to be higher in average than without the review course.

D. P(z>0.94)=0.1736

Step-by-step explanation:

<em>A. state the null and alternative hypotheses.</em>

The null hypothesis states that the review course has no effect, so the scores are still the same. The alternative hypothesis states that the review course increase the score.

H_0: \mu\leq514\\\\H_1: \mu>514

B. test the hypothesis at the a=.10 level of confidence. is a mean math score of 520 significantly higher than 514? find the test statistic, find P-value. is the sample statistic significantly higher?

The test statistic Z can be calculated as

Z=\frac{M-\mu}{s/\sqrt{N}} =\frac{520-514}{119/\sqrt{2000}}=\frac{6}{2.661}=2.255

The P-value of z=2.255 is P=0.01207.

The P-value is smaller than the significance level, so the effect is significant. The null hypothesis is rejected.

Then we can conclude that the score of 520 is significantly higher than 514, in this case, specially because the big sample size.

C.​ do you think that a mean math score of 520 vs 514 will affect the decision of a school admissions adminstrator? in other words does the increase in the score have any practical significance?

Although it is not big difference, it is an improvement that has evidence. The scores are expected to be higher in average than without the review course.

D. test the hypothesis at the a=.10 level of confidence with n=350 students. assume that the sample mean is still 520 and the sample standard deviation is still 119. is a sample mean of 520 significantly more than 514? find test statistic, find p value, is the sample mean statisically significantly higher? what do you conclude about the impact of large samples on the p-value?

In this case, the z-value is

Z=\frac{520-514}{s/\sqrt{n}} =\frac{6}{119/\sqrt{350}} =\frac{6}{6.36} =0.94\\\\P(z>0.94)=0.1736>\alpha

In this case, the P-value is greater than the significance level, so there is no evidence that the review course is increasing the scores.

The sample size gives robustness to the results of the sample. A large sample is more representative of the population than a smaller sample. A little difference, as 520 from 514, but in a big sample leads to a more strong evidence of a change in the mean score.

Large samples give more extreme values of z, so P-values that are smaller and therefore tend to be smaller than the significance level.

8 0
3 years ago
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