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Elza [17]
3 years ago
9

a small jet can fly 1,435 miles in 5 hours with a tailwind but only 1,215 miles in 5 hours into a headwind. find the speed of th

e jet in still air and the speed of the wind.​

Mathematics
1 answer:
Ne4ueva [31]3 years ago
4 0

Answer:

Speed of Jet in Still Air = 265 miles per hour

Speed of Wind = 22 miles per hour

Step-by-step explanation:

Let x be speed of jet

and c be speed of wind

We know D = RT, where

D is distance

R is rate

T is time

For first leg:

1435 miles in 5 hours, the rate is:

Rate = 287 mph

For second leg:

1215 miles in 5 hours, the rate is:

Rate = 243 mph

So 287 is with wind and 243 against wind, thus we can write:

x + c = 287

x - c = 243

Adding gives us:

2x = 530

x = 265 miles per hour [still rate]

Speed of wind:

x + c = 287

265 + c = 287

c = 22 miles per hour [speed of wind]

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48 divided by sqrt of 9.5 =

48 divided by 3.082207 = 15.57325643605378 is your answer

4 0
3 years ago
Distance between parallel lines y=3x+10 and y=3x-20
Alecsey [184]

1. Take an arbitrary point that lies on the first line y=3x+10. Let x=0, then y=10 and point has coordinates (0,10).


2. Use formula d=\dfrac{|Ax_0+By_0+C|}{\sqrt{A^2+B^2}} to find the distance from point (x_0,y_0) to the line Ax+By+C=0.


The second line has equation y=3x-20, that is 3x-y-20=0. By the previous formula the distance from the point (0,10) to the line 3x-y-20=0 is:

d=\dfrac{|3\cdot 0-10-20|}{\sqrt{3^2+(-1)^2}}=\dfrac{30}{\sqrt{10}}=3\sqrt{10}.


3. Since lines y=3x+10 and y=3x-20 are parallel, then the distance between these lines are the same as the distance from an arbitrary point from the first line to the second line.


Answer: d=3\sqrt{10}.

4 0
3 years ago
What is the name of the intersection point? Explain.
MariettaO [177]
<h3>Answer: Midpoint</h3>

Explanation:

The drawings you made are constructions of the perpendicular bisector. The "perpendicular" refers to the fact the second line meets the first line at a right angle (aka 90 degree angle). The "bisector" portion indicates the segment has been bisected, which is mathematical way of saying "cut in half".

The key here is the "bisector" portion. Because we've cut a segment like AB in half, this means segment AC and CB are the same length. The point C is the midpoint of AB. Point C is formed by intersecting the perpendicular bisector and the original segment. I'm referring to drawing (a), but the same idea applies to drawing (b) as well. I recommend using another letter than C for the second drawing.

6 0
2 years ago
Frank and Gertrude mow lawns for extra money over the summer. Frank's income is determined by f(x) = 5x + 15, where x is the num
lys-0071 [83]

Answer:

d. h(x) = 9x + 35, team with Gertrude

Step-by-step explanation:

Just took the test XD.

But also it is solved by simply adding 4x+20 and 5x+15

7 0
3 years ago
A company that produces dog food claims that its bags contain 11 kg of food. From
andriy [413]

By testing the hypothesis we can conclude that the bag does not contain 11 kg of food.

Given mean of 10.6 kg, population standard deviation of 0.6 and sample size of 25.

We are required to find whether the company is right in saying that their bags contain 11 kg of food.

First we have to make hypothesis.

H_{0}:μ≠11

H_{1}:μ=11

We have to use t statistic because the sample size is less than 30.

t=(X-μ)/s/\sqrt{n}

We will use s/\sqrt{n}=0.6 because we have already given population standard deviation of weights.

t=(11-10.6)/0.6

=0.4/0.6

=0.667

Degree of freedom=n-1

=25-1

=24

T critical at 0.05 with degree of freedom 24=2.0639

T critical at 0.05 with degree of freedom is greater than calculated t so we will accept the null hypothesis.It concludes that the bags donot contain 11 kg of food.

Hence by testing the hypothesis we can conclude that the bag does not contain 11 kg of food.

Learn more about t test at brainly.com/question/6589776

#SPJ1

3 0
2 years ago
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