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wlad13 [49]
3 years ago
11

The amount of rainfall in january in a certain city is normally distributed with a mean of 4.3 inches and a standard deviation o

f 0.3 inches. find the value of the quartile q1. 1.1 4.2 4.1 4.5

Mathematics
1 answer:
Sholpan [36]3 years ago
7 0
We start by showing the position of the first quartile, Q1 on the normal distribution graph. Q1 happens at 25% of the data.

The graph is shown below

We are interested in the area to the left of Q1 and we know that the probability is 0.25

We can find out the value of z-score from the table as shown below 

The z-score when p=0.25 is 0.68

then changing this z-score into the actual value

-0.68= \frac{X-4.3}{0.3}
-0.204=X-4.3
X=4.096

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2 ^ x - 12/2 ^ x is equal to -4​
Anastaziya [24]

Answer:

-3071/16

Step-by-step explanation:

Hope this helps, if you wrote it wrong or need help understanding please let me know!

4 0
3 years ago
Jane and Lee had dinner at The Palace The bill totaled $20 30 with tax The service
kirza4 [7]

Answer:

$3.45

Step-by-step explanation:

$20.30 / 10  = $2.30 = 10%

$2.30 / 2  = $1.15 = 5%

$2.30 + $1.15 = $3.45 = 15%

3 0
3 years ago
Which expression is a linear factor of x6 +x-66?
Naddik [55]

Answer:

Option D.

Step-by-step explanation:

The given expression is

x^6+x-66

It is a polynomial.

(x-c) is a linear factor of polynomial p(x) if p(c)=0.

Substitute x=-1 in the given expression.

(1)^6+(1)-66=-64\neq 0

It means (x+1) is not a linear factor of given expression.

Substitute x=-2 in the given expression.

(-2)^6+(-2)-66=-4\neq 0

It means (x+2) is not a linear factor of given expression.

Substitute x=-4 in the given expression.

(-4)^6+(-4)-66=4026\neq 0

It means (x+4) is not a linear factor of given expression.

None of the given options are a linear factor of given expression.

Therefore, the correct option is D.

7 0
3 years ago
Read 2 more answers
A bacteria colony increases in size at a rate of 4.0581e1.6t bacteria per hour. If the initial population is 36 bacteria, find t
Harrizon [31]

Answer:

1560

Step-by-step explanation:

The rate of Increase of the population (P) of the bacteria is given as:

\frac{dP}{dt} =4.058e^{1.6t}

dP =4.058e^{1.6t}}dt\\Taking\: Integrals\\\int dP =4.058 \int e^{1.6t}dt\\P(t)=\frac{4.058}{1.6} (e^{1.6t} +K)\\P(t)=2.53625 (e^{1.6t} +K)

Where k is a constant of Integration.

At t=0, P(t)=36

36=2.53625 (e^{1.6*0} +K)\\36=2.53625 (e^{0} +K)\\36=2.53625 (1 +K)\\36=2.53625 +2.53625K\\K=13.19

Therefore:

P(t)=2.53625 (e^{1.6t} +13.19)\\At \: t=4\\P(4)=2.53625 (e^{1.6*4} +13.19)\\=1559.88\\P(4)=1560

3 0
3 years ago
If m<9=97 and m<12=114, find each measure.
seropon [69]

Answer:

a. 97

b. 83

c.66

d. 114

e.83

f. 97

g. 114

h.66

i. 83

j. 66

k.83

l.97

m. 114

n. 66

6 0
3 years ago
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