Which of the following expression is equal to x^2+25?
2 answers:
The answer is (x-5i)(x+5i)
A: (x + 5i)^2 = (x + 5i)(x + 5i) = (x)(x) + (x)(5i) + (5i)(x) + (5i)(5i) = x^2 + 5ix + 5ix + 25i^2 = 25i^2 + 10ix + x^2 B: (x - 5i)^2 = (x + - 5i)(x + - 5i) = (x)(x) + (x)(- 5i) + (- 5i)(x) + (- 5i)(- 5i) = x^2 - 5ix - 5ix + 25i^2 = 25i^2 - 10ix + x^2 C: (x - 5i)(x + 5i) = (x + - 5i)(x + 5i) = (x)(x) + (x)(5i) + (- 5i)(x) + (- 5i)(5i) = x^2 + 5ix - 5ix - 25i^2 = 25i^2 + x^2 D: (x + 10i)(x - 15i) = (x + 10i)(x + - 15i) = (x)(x) + (x)(- 15i) + (10i)(x) + (10i)(- 15i) = x^2 - 15ix + 10ix - 150i^2 = - 150i^2 + 5ix + x^2 Hope that helps!!!
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