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dmitriy555 [2]
3 years ago
10

Find the area of the composite figure in terms of pie 3cm Length and 5 cm in width

Mathematics
1 answer:
cluponka [151]3 years ago
5 0
The area will be 15
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If Upper A equals StartSet x | x is an even integer EndSet commaA={x | x is an even integer}, Upper B equals StartSet x | x is a
White raven [17]

Answer:

C ∪ D = {2, 3, 4, 5, 8, 9, 10, 11}

Step-by-step explanation:

A={x | x is an even integer}

B={x | x is an odd integer},

C={2, 3, 4, 5},

D={8, 9, 10, 11}.

A union of two or more sets is the collection of the members of the sets in a set without repeating any element.

Given sets C and D above, the union of the two sets is the set:

C ∪ D = {2, 3, 4, 5, 8, 9, 10, 11}

Note: The Intersection is the collection of sets that are common to C and D. in this case no element is common, therefore the intersection is a Null Set.

8 0
3 years ago
Hours<br>7 2/3<br>1 2/5<br>4 3/4<br>8 4/5​
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1. 7 hours and 40 min
2. 1 hour and 24 min
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3 0
2 years ago
In each basket of fruit, there are 3 more apples than pears.
olga nikolaevna [1]

Answer:

p=a+3 okkkkkkkkkkkkkkkkkkkkk

4 0
2 years ago
Help me pls i keep getting 3/2 but thats not the answer
Gemiola [76]

\huge\text{Hey there!}

\large\boxed{\mathsf{\dfrac{6x^2}{y^3}}}\\\\\large\boxed{= \mathsf{\dfrac{6(4^2)}{4^3}}}\\\\\large\boxed{= \mathsf{\dfrac{6(4\times4)}{4\times4\times4}}}\\\\\large\boxed{= \mathsf{\dfrac{96}{16\times4}}}}\\\\\large\boxed{= \mathsf{\dfrac{96}{64}}}\\\large\boxed{\approx \mathsf{\dfrac{96\div32}{64\div32}}}\\\large\boxed{\approx \mathsf{\dfrac{3}{2} \rightarrow \bf \dfrac{96}{64}}}

\huge\text{Thus, your answer is: \boxed{\mathsf{Option\ A. } \  \mathsf{\dfrac{96}{64}}}}\huge\checkmark

\huge\text{Good luck on your assignment \& enjoy}\\\huge\text{your day!}

~\frak{Amphitrite1040:)}

3 0
2 years ago
Read 2 more answers
3- 2 1/3×3/14+1 1/3÷4/5
Romashka [77]

Answer:

4.166 or 4.17 or 4 7/100

Step-by-step explanation:

Please consider giving me brainliest.

Have a good day<3 Bye!

6 0
2 years ago
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