1.B - - original function is y = sqrt(x). If we make sqrt(x+4), we will move the original function to the left 4. If we make sqrt(x+4)+3, additionally the original function will be moved up 3.
2.D - original function is y = sqrt(x). If we make sqrt(x-7), we will move the original function to the right 7. If we make 5*sqrt(x-7), additionally the original function will be expanded throw the y-axis.
3.E - original function is y = x^5. If we make -x^5 (multiply x^2 by -1), we will reflect the original function over the x-axis. If we make -x^5 - 4 , we additionally will move the original function down 4.
4.C - original function is y = x^2. If we make (x-3)^2, we will move the original function to the right 3. If we make x^2 - 5 , we will move the original function down 5.
5.A - original function is y = x^2. If we multiply x^2 by 1/3, function will be compressed about the y-axis.
Question 1:
Perimeter = 18ft
area = 15ft²
Question 2:
Perimeter = 11m
Area = 7.5m²
Answer:
x = 30
Step-by-step explanation:
here 50 is hypotenuse as it is opposite of 90 degree.
x and x + 10 are the two other smaller sides of a right angled triangle respectively.
using pythagoras theorem,
a^2 + b^2 = c^2
x^2 + (x + 10)^2 = 50^2
x^2 + x^2 + 20x + 100 = 2500
2x^2 + 20x + 100 = 2500
2x^2 + 20x + 100 - 2500 = 0
2x^2 + 20x - 2400 = 0
2(x^2 + 10x - 1200) = 0
x^2 + 10x - 1200 = 0
x^2 + (40 - 30) - 1200 = 0
x^2 + 40x - 30x - 1200 = 0
x(x + 40) - 30(x + 40x) = 0
(x + 40)(x - 30) = 0
either x + 40 = 0 OR x - 30 = 0
x = 0 - 40
x = -40
x - 30 = 0
x = 30
x = -40,30
since the length and distance is not measured in negative ur answer will be 30
credit goes to sreedevi102
thank u very much . At first i was wrong and giannathecookie i m really sorry
Answer: 92
Step-by-step explanation: Angles in an inscribed quad are supplementary and add to 360.
First solve for x:
2x+34=180
x = 73
Then, solve for c
3x + 49 + c = 360
3(73) + 49 + c = 360
268 + c = 360
c = 92
Answer:
Step-by-step explanation:
We want to find equation of a circle with center (-4,6) and radius 9cm.
The equation of a circle with center (h,k) and radius 
units is given by;
We substitute the radius and the center to obtain;
The required equation is:
