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lisov135 [29]
3 years ago
8

(2, -1) is a solution to which of the following systems of equations?

Mathematics
2 answers:
abruzzese [7]3 years ago
8 0

Answer:

D) 3x + y = 5 and 2x -3y = 7

Step-by-step explanation:

You can plug in the x and y values into the equations, and see if they work. In this case, 3x + y = 5 and 2x -3y = 7 both satisfy (2, -1).

GuDViN [60]3 years ago
8 0

Answer:

the answer it D

Step-by-step explanation:

3(2)-1=5

and 2(2)+3=7

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ALGEBRA HELP ASAP!! THANK YOU IN ADVANCE
Alina [70]
1.B -  - original function is y = sqrt(x). If we make sqrt(x+4), we will move the original function to the left 4. If we make sqrt(x+4)+3, additionally the original function will be moved up 3.

2.D - original function is y = sqrt(x). If we make sqrt(x-7), we will move the original function to the right 7. If we make 5*sqrt(x-7), additionally the original function will be expanded throw the y-axis.

3.E - original function is y = x^5. If we make -x^5 (multiply x^2 by -1), we will reflect the original function over the x-axis. If we make -x^5 - 4 , we additionally will move the original function down 4.

4.C - original function is y = x^2. If we make (x-3)^2, we will move the original function to the right 3. If we make x^2 - 5 , we will move the original function down 5.

5.A - original function is y = x^2. If we multiply x^2 by 1/3, function will be compressed about the y-axis.
6 0
3 years ago
Answers to 1-6 please :)
nikitadnepr [17]
Question 1:
Perimeter = 18ft
area = 15ft²
Question 2:
Perimeter = 11m
Area = 7.5m²
4 0
4 years ago
What is the value of x in the diagram?
dalvyx [7]

Answer:

x = 30

Step-by-step explanation:

here 50 is hypotenuse as it is opposite of 90 degree.

x and x + 10 are the two other smaller sides of a right angled triangle respectively.

using pythagoras theorem,

a^2 + b^2 = c^2

x^2 + (x + 10)^2 = 50^2

x^2 + x^2 + 20x + 100 = 2500

2x^2 + 20x + 100 = 2500

2x^2 + 20x + 100 - 2500 = 0

2x^2 + 20x - 2400 = 0

2(x^2 + 10x - 1200) = 0

x^2 + 10x - 1200 = 0

x^2 + (40 - 30) - 1200 = 0

x^2 + 40x - 30x - 1200 = 0

x(x + 40) - 30(x + 40x) = 0

(x + 40)(x - 30) = 0

either x + 40 = 0          OR x - 30 = 0

x = 0 - 40

x = -40

x - 30 = 0

x = 30

x = -40,30

since the length and distance is not measured in negative ur answer will be 30

credit goes to sreedevi102

thank u very much . At first i was wrong and giannathecookie i m really sorry

3 0
3 years ago
Read 2 more answers
Urgent! <br>Quadrilateral ABCD is inscribed in the circle. What is the measure of angle C?​
AnnyKZ [126]

Answer: 92

Step-by-step explanation: Angles in an inscribed quad are supplementary and add to 360.

First solve for x:

2x+34=180

x = 73

Then, solve for c

3x + 49 + c = 360

3(73) + 49 + c = 360

268 + c = 360

c = 92

3 0
3 years ago
What is the equation of a circle whose center is begin ordered pair negative 4 comma 6 end ordered pair and whose radius is 9 cm
solong [7]

Answer:

(x+4)^2+(y-6)^2=81

Step-by-step explanation:

We want to find equation of a circle with center (-4,6) and radius 9cm.

The equation of a circle with center (h,k) and radius r units is given by;

(x-h)^2+(y-k)^2=r^2

We substitute the radius and the center to obtain;

(x+4)^2+(y-6)^2=9^2

The required equation is:

(x+4)^2+(y-6)^2=81

3 0
3 years ago
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